参数资料
型号: AD7441BRMZ
厂商: Analog Devices Inc
文件页数: 10/25页
文件大小: 0K
描述: IC ADC 10BIT PSDO IN 1MSPS 8MSOP
标准包装: 50
位数: 10
采样率(每秒): 1M
数据接口: DSP,MICROWIRE?,QSPI?,串行,SPI?
转换器数目: 1
功率耗散(最大): 9.25mW
电压电源: 单电源
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 8-TSSOP,8-MSOP(0.118",3.00mm 宽)
供应商设备封装: 8-MSOP
包装: 管件
输入数目和类型: 1 个伪差分,单极
AD7441/AD7451
Rev. D | Page 17 of 24
Timing Example 2
Timing Example 1
Having fSCLK = 5 MHz and a throughput rate of 315 kSPS gives a
cycle time of
Having fSCLK = 18 MHz and a throughput rate of 1 MSPS gives a
cycle time of
1/Throughput = 1/315,000 = 3.174 μs
1/Throughput = 1/1,000,000 = 1 μs
A cycle consists of
t2 + 12.5 (1/fSCLK) + tACQUISITION = 3.174 μs
t2 + 12.5 (1/fSCLK) + tACQUISITION = 1 μs
Therefore, if t2 is 10 ns, then
Therefore, if t2 = 10 ns, then
10 ns + 12.5 (1/5 MHz) + tACQUISITION = 3.174 μs
tACQUISITION = 664 ns
10 ns + 12.5 (1/18 MHz) + tACQUISITION = 1 μs
tACQUISITION = 296 ns
This 664 ns satisfies the requirement of 290 ns for tACQUISITION.
This 296 ns satisfies the requirement of 290 ns for tACQUISITION.
From Figure 28, tACQUISITION comprises
From Figure 28, tACQUISITION comprises
2.5 (1/fSCLK) + t8 = tQUIET
where t8 = 35 ns. This allows a value of 129 ns for tQUIET,
satisfying the minimum requirement of 60 ns.
where t8 = 35 ns. This allows a value of 122 ns for tQUIET,
satisfying the minimum requirement of 60 ns.
As in this example and with other slower clock values, the signal
can already be acquired before the conversion is complete, but it
is still necessary to leave 60 ns minimum tQUIET between conver-
sions. In Example 2, the signal is fully acquired at approximately
Point C in Figure 28.
t2
t8
t6
t5
tCONVERT
CS
SCLK
12
3
4
5
13
14
15
16
12.5(1/
fSCLK)
tACQUISITION
1/THROUGHPUT
tQUIET
10ns
B
C
03
15
3-
02
8
Figure 28. Serial Interface Timing Example
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