参数资料
型号: AT89C51ID2-SLRIM
厂商: Atmel
文件页数: 106/157页
文件大小: 0K
描述: IC MCU FLASH 8051 64K 5V 44-PLCC
标准包装: 1
系列: 89C
核心处理器: 8051
芯体尺寸: 8-位
速度: 60MHz
连通性: I²C,SPI,UART/USART
外围设备: POR,PWM,WDT
输入/输出数: 34
程序存储器容量: 64KB(64K x 8)
程序存储器类型: 闪存
EEPROM 大小: 2K x 8
RAM 容量: 2K x 8
电压 - 电源 (Vcc/Vdd): 2.7 V ~ 5.5 V
振荡器型: 外部
工作温度: -40°C ~ 85°C
封装/外壳: 44-LCC(J 形引线)
包装: 剪切带 (CT)
其它名称: AT89C51ID2SLRIMCT
52
AT89C51ID2
4289C–8051–11/05
Serial I/O Port
The serial I/O port in the AT89C51ID2 is compatible with the serial I/O port in the 80C52.
It provides both synchronous and asynchronous communication modes. It operates as a
Universal Asynchronous Receiver and Transmitter (UART) in three full-duplex modes
(Modes 1, 2 and 3). Asynchronous transmission and reception can occur simultaneously
and at different baud rates
Serial I/O port includes the following enhancements:
Framing error detection
Automatic address recognition
Framing Error Detection
Framing bit error detection is provided for the three asynchronous modes (modes 1, 2
and 3). To enable the framing bit error detection feature, set SMOD0 bit in PCON regis-
ter (See Figure 20).
Figure 20. Framing Error Block Diagram
When this feature is enabled, the receiver checks each incoming data frame for a valid
stop bit. An invalid stop bit may result from noise on the serial lines or from simultaneous
transmission by two CPUs. If a valid stop bit is not found, the Framing Error bit (FE) in
SCON register (See Table 38.) bit is set.
Software may examine FE bit after each reception to check for data errors. Once set,
only software or a reset can clear FE bit. Subsequently received frames with valid stop
bits cannot clear FE bit. When FE feature is enabled, RI rises on stop bit instead of the
last data bit (See Figure 21. and Figure 22.).
Figure 21. UART Timings in Mode 1
RI
TI
RB8
TB8
REN
SM2
SM1
SM0/FE
IDL
PD
GF0
GF1
POF
-
SMOD0
SMOD1
To UART framing error control
SM0 to UART mode control (SMOD0 = 0)
Set FE bit if stop bit is 0 (framing error) (SMOD0 = 1)
SCON (98h)
PCON (87h)
Data byte
RI
SMOD0=X
Stop
bit
Start
bit
RXD
D7
D6
D5
D4
D3
D2
D1
D0
FE
SMOD0=1
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