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| 型号： | DC-2R5E224U-E |
| 厂商： | Elna America |
| 文件页数： | 115/145页 |
| 文件大小： | 0K |
| 描述： | CAP SUPER 220MF 2.5V COIN SMD |
| 产品目录绘图： | DC Series Front DC Series Side |
| 标准包装： | 200 |
| 系列： | DC |
| 电容： | 220mF |
| 电压 - 额定： | 2.5V |
| 容差： | -20%，+80% |
| ESR（等效串联电阻）： | 100 欧姆 |
| 寿命@温度： | 70°C 时为 1000 小时 |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 币形，细型端子 - 同侧 |
| 引线间隔： | 0.079"（2.00mm） |
| 包装： | 散装 |
| 尺寸/尺寸： | 0.268" 直径（6.80mm） |
| 高度 - 座高（最大）： | 0.102"（2.60mm） |
| 工作温度： | -25°C ~ 70°C |
| 产品目录页面： | 1912 (CN2011-ZH PDF) |
| 其它名称： | 604-1006 |
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TECHNICAL NOTE
ALUMINUM ELECTROLYTIC
CAPACITORS
?
3 To calculate Balance when connecting in
series
3-1 Circuit layout
Circuit for connecting two capacitors (C1, C2) in series
If a ＝ 0.8, 400(V)×2×0.8 ＝ 640(V) as an impressed
voltage.
If b ＝ 2, R 2 ＝ b R 1 ＝ 426(kΩ), LC ＝ 0.94(mA).
Balance resistance R B will be.
and equivalent circuit can be illustrated as below figure.
Formula to calculate a balance resistance R B of below
R B ≦ 2×2×213(kΩ)
(1?0.8)
(2×0.8)×2?1
＝ 852(k Ω )
figure is shown as follows.
4 Regarding Recovery Voltage
C 1
R B
R 1
R B
V 1
? After charging and then discharging the aluminum
electrolytic capacitor, and further causing short-circuit
V
to the terminals and leave them alone, the voltage
C 2
R B
R 2
R B
V 2
between the two terminals will rise again after some
interval. Voltage caused in such case is called recovery
voltage. Following is the process that causes this
phenomenon :
Following are the preconditions of the circuit.
① V 2 shall be the rated voltage ( ＝ V 0 ). (V 1 ＜ V 2 )
? When the voltage is impressed on a dielectric,
electrical transformation will be caused inside the
② V shall be a times V 0 × 2. V ＝ 2aV 0
(a ＜ 1)
dielectric due to dielectric action, and electrification
③ R 2 shall equal R 1 × b. (b ＜ 1) (1)
3-2 Formulas to calculate [R B ]
3-2-1 Following formula can be established from
balanced condition.
will occur in positive-negative opposite to the voltage
impressed on the surface of the dielectric. This
phenomenon is called polarization action.
? After the voltage is impressed with this polarization
action, and if the terminals are discharged till the
V 1
1 ＋ 1
R 1 R B
＝ V 2
1 ＋ 1
R 2 R B
(2)
terminal voltage reaches 0 and are left open for a while,
an electric potential will arise between the two terminals
and thus causes recovery voltage.
3-2-2 Following formula can be established from
preconditions.
? Recovery voltage comes to a peak around 10 to 20
days after the two terminals are left open, and then
V 2 ≦ V 0
V 1 ＝ V ? V 2
＝ 2aV 0 ? V 2
(3)
(4)
(4’)
gradually declines. Recovery voltage has a tendency to
become bigger as the component (stand-alone base
type) becomes bigger.
? If the two terminals are short-circuited after the
＝ V 2
(2aV 0 ? V 2 )
3-2-3 Put formulas (1), (3) and (4’) in formula (2).
R 1 ＋ R B bR 1 ＋ R B
R 1 ? R B bR 1 ? R B
2abV 0 (R 1 ＋ R B ) ＝ V 2 {b(R 1 ＋ R B ) ＋ bR 1 ＋ R B }
2ab(R 1 ＋ R B ) ≦ 2bR 1 ＋ (1 ＋ b)R B
Accordingly, balance resistance R shall be the
following formula.
recovery voltage is generated, a spark may scare the
workers working in the assembly line, and may put low -
voltage driven components (CPU, memory, etc.) in
danger of being destroyed. Measures to prevent this is
to discharge the accumulated electric charge with
resistor of about 100 to 1k Ω before using, or ship out
by making the terminals in short-circuit condition by
R B ≦2bR 1
(1 ? a)
(2a ? 1) ? b ? 1
(5)
covering them with an aluminum foil at the production
stage. Please consult us for adequate procedures.
3-3 Calculation Example.
Calculate the value of the balance resistance in the
case of connecting two 400V 470μF ( LC standard
value : 1.88mA) capacitors in series.
R 1 ＝
400(V)
1.88(mA)
＝ 213(k Ω )
NOTE
CAT.No.2008/2009E(2008.10.1)
Design, Speci?cations are subject to change without notice.
Ask factory for technical speci?cations before purchase and/or use.
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