参数资料
型号: FC250A11
元件分类: 电源模块
英文描述: 1-OUTPUT 100 W DC-DC REG PWR SUPPLY MODULE
文件页数: 3/16页
文件大小: 262K
代理商: FC250A11
Tyco Electronics Corp.
11
Data Sheet
July 1998
18 Vdc to 36 Vdc Input, 5 Vdc Output; 50 W
FC250A1 Power Module: dc-dc Converter;
Thermal Considerations (continued)
Heat Transfer Without Heat Sinks (continued)
8-3400 (F)
Figure 16. FC250A1 Power Dissipation vs.
Output Current at 25 °C
Heat Transfer with Heat Sinks
The power modules have through-threaded, M3 x 0.5
mounting holes, which enable heat sinks or cold plates
to attach to the module. The mounting torque must not
exceed 0.56 N-m (5 in.-lb.).
Thermal derating with heat sinks is expressed by using
the overall thermal resistance of the module. Total
module thermal resistance (
θca) is defined as the max-
imum case temperature rise (
TC, max) divided by the
module power dissipation (PD):
The location to measure case temperature (TC) is
shown in Figure 14. Case-to-ambient thermal resis-
tance vs. airflow is shown, for various heat sink config-
urations and heights, in Figure 17. These curves were
obtained by experimental testing of heat sinks, which
are offered in the product catalog.
8-3365.a
Figure 17. FC250A1 Case-to-Ambient Thermal
Resistance Curves; Either Orientation
These measured resistances are from heat transfer
from the sides and bottom of the module as well as the
top side with the attached heat sink; therefore, the
case-to-ambient thermal resistances shown are gener-
ally lower than the resistance of the heat sink by itself.
The module used to collect the data in Figure 17 had a
thermal-conductive dry pad between the case and the
heat sink to minimize contact resistance. The use of
Figure 17 is shown in the following example.
Example
If an 85 °C case temperature is desired, what is the
minimum airflow necessary? Assume the FC250A1
module is operating at VI = 54 V and an output current
of 26 A, maximum ambient air temperature of 55 °C,
and the heat sink is 1/4 inch.
Solution
Given: VI = 54 V
IO = 26 A
TA = 55 °C
TC = 85 °C
Heat sink = 1/4 inch
Determine PD by using Figure 16:
PD = 10 W
20
4
OUTPUT CURRENT, IO (A)
P
O
WER
D
ISSI
PATI
O
N
,
P
D
(W)
6 8 10 12 14
18
16
14
12
10
8
6
4
2
16 18 20 22 24 26 28 30 32 34 36 38 40
VI = 75 V
VI = 54 V
VI = 36 V
θca
TCmax
,
PD
---------------------
TC
TA
()
PD
------------------------
==
8
7
6
5
4
3
2
1
0
CASE-T
O-AMBIENT
THERMAL
RESIST
ANCE,
θ
CA
(C/W)
0
0.5
(100)
1.0
(200)
1.5
(300)
2.0
(400)
2.5
(500)
3.0
(600)
1 1/2 IN. HEAT SINK
1 IN. HEAT SINK
1/2 IN. HEAT SINK
1/4. HEAT SINK
NO HEAT SINK
AIR VELOCITY MEASURED IN m/s (ft./min.)
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