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参数资料
| 型号： | FC250R1 |
| 厂商： | LINEAGE POWER LLC |
| 元件分类： | 电源模块 |
| 英文描述： | 1-OUTPUT 252 W DC-DC REG PWR SUPPLY MODULE |
| 封装： | MODULE-20 |
| 文件页数： | 5/20页 |
| 文件大小： | 583K |
| 代理商： | FC250R1 |
Lineage Power
13
Data Sheet
April 2008
dc-dc Converter; 18 Vdc to 36 Vdc Input, 28 Vdc Output; 250 W
FC250R Power Module:
Thermal Considerations (continued)
Heat Transfer With Heat Sinks (continued)
8-1320 (C)
Figure 22. Case-to-Ambient Thermal Resistance
Curves; Longitudinal Orientation
These measured resistances are from heat transfer
from the sides and bottom of the module as well as the
top side with the attached heat sink; therefore, the
case-to-ambient thermal resistances shown are gener-
ally lower than the resistance of the heat sink by itself.
The module used to collect the data in Figures 21 and
22 had a thermal-conductive dry pad between the case
and the heat sink to minimize contact resistance.
To choose a heat sink, determine the power dissipated
as heat by the unit for the particular application.
Figure 23 shows typical heat dissipation for a range of
output currents and three voltages for the FC250R.
8-2471 (C)
Figure 23. FC250R Power Dissipation vs. Output
Current
Example
If an 85 °C case temperature is desired, what is the
minimum airow necessary? Assume the FC250R
module is operating at nominal line and an output cur-
rent of 9.0 A, maximum ambient air temperature of
40 °C, and the heat sink is 0.5 inch.
Solution
Given: VI = 28 V
IO = 9.0 A
TA = 40 °C
TC = 85 °C
Heat sink = 0.5 inch.
Determine PD by using Figure 23:
PD = 34 W
Then solve the following equation:
Use Figures 21 and 22 to determine air velocity for the
0.5 inch heat sink. The minimum airow necessary for
this module depends on heat sink n orientation and is
shown below:
s
1.6 m/s (320 ft./min.) (oriented along width)
s
2.0 m/s (400 ft./min.) (oriented along length)
Custom Heat Sinks
A more detailed model can be used to determine the
required thermal resistance of a heat sink to provide
necessary cooling. The total module resistance can be
separated into a resistance from case-to-sink (
θcs) and
θsa) as shown in Figure 24.
8-1304 (C)
Figure 24. Resistance from Case-to-Sink and Sink-
to-Ambient
0
0.5
(100)
1.0
(200)
1.5
(300)
2.0
(400)
2.5
(500)
3.0
(600)
AIR VELOCITY, m/s (ft./min.)
0.0
0.5
3.0
3.5
4.0
4.5
2.5
2.0
1.0
CASE-TO-AMBIENT
THERMAL
RESISTANCE,
R
CA
(
°C/W)
1 1/2 in. HEAT SINK
1 in. HEAT SINK
1/2 in. HEAT SINK
1/4 in. HEAT SINK
NO HEAT SINK
1.5
234567
0
35
OUTPUT CURRENT, IO (A)
25
20
30
40
1
5
VI = 36 V
VI = 28 V
VI = 18 V
10
15
POWER
DISSIPATION,
P
D
(W)
9
8
θca
TC
TA
–
()
PD
------------------------
=
θca
85
40
–
()
34
------------------------
=
θca 1.32 °C/W
=
PD
TC
TS
TA
cs
sa
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