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参数资料
| 型号： | HA9P2556-9 |
| 厂商： | Intersil |
| 文件页数： | 14/18页 |
| 文件大小： | 0K |
| 描述： | IC MUX ANALOG 57MHZ MONO 16-SOIC |
| 标准包装： | 48 |
| 功能： | 模拟乘法器 |
| 位元/级数： | 四象限 |
| 封装/外壳： | 16-SOIC（0.295"，7.50mm 宽） |
| 供应商设备封装： | 16-SOIC |
| 包装： | 管件 |
5
FN2477.7
April 25, 2013
Simplified Schematic
Application Information
Operation at Reduced Supply Voltages
The HA-2556 will operate over a range of supply voltages,
±5V to ±15V. Use of supply voltages below ±12V will reduce
input and output voltage ranges. See “Typical Performance
Curves” on page 12 for more information.
Offset Adjustment
X-Channel and Y-Channel offset voltages may be nulled by
using a 20k potentiometer between the VYIO or VXIO adjust
pin A and B and connecting the wiper to V-. Reducing the
channel offset voltage, will reduce AC feedthrough and
improve the multiplication error. Output offset voltage can
also be nulled by connecting VZ- to the wiper of a
potentiometer which is tied between V+ and V-.
Capacitive Drive Capability
When driving capacitive loads >20pF a 50
Ω resistor should
be connected between VOUT and VZ+, using VZ+ as the
output (see Figure 1). This will prevent the multiplier from
going unstable and reduce gain peaking at high frequencies.
The 50
Ω resistor will dampen the resonance formed with the
capacitive load and the inductance of the output at Pin 8.
Gain accuracy will be maintained because the resistor is
inside the feedback loop.
Theory of Operation
The HA-2556 creates an output voltage that is the product
of the X and Y input voltages divided by a constant scale
factor of 5V. The resulting output has the correct polarity in
each of the four quadrants defined by the combinations of
positive and negative X and Y inputs. The Z stage provides
the means for negative feedback (in the multiplier
configuration) and an input for summation into the output.
This results in Equation 1, where X, Y and Z are high
impedance differential inputs.
To accomplish this the differential input voltages are first
converted into differential currents by the X and Y input
transconductance stages. The currents are then scaled by a
constant reference and combined in the multiplier core. The
multiplier core is a basic Gilbert Cell that produces a
differential output current proportional to the product of X and
Y input signal currents. This current becomes the output for
the HA-2557.
The HA-2556 takes the output current of the core and feeds it
to a transimpedance amplifier, that converts the current to a
voltage. In the multiplier configuration, negative feedback is
provided with the Z transconductance amplifier by connecting
VOUT to the Z input. The Z stage converts VOUT to a current
which is subtracted from the multiplier core before being
applied to the high gain transimpedance amp. The Z stage, by
virtue of it’s similarity to the X and Y stages, also cancels
second order errors introduced by the dependence of VBE on
collector current in the X and Y stages.
VBIAS
OUT
VZ-
VCC
VZ+
V-
V+
VYIOA
VYIOB
VY-
VY+
VXIOAVXIOB
VX+
REF
GND
VX-
+
-
VBIAS
NC
VY+
-15V
VOUT
+15V
VX+
NC
50
Ω
1k
Ω
20pF
NC
VZ-
VZ+
14
15
16
9
13
12
11
10
1
2
3
4
5
7
6
8
Σ
+ -
REF
+
-
+
-
+
-
FIGURE 1. DRIVING CAPACITIVE LOAD
V
OUT = Z
X x Y
5
--------------
=
(EQ. 1)
HA-2556
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相关代理商/技术参数 |
参数描述 |
|---|---|
| HA9P2556-9Z | 功能描述:隔离放大器 W/ANNEAL MULT 4-QDRA V-OUT ANALOG 16W IND RoHS:否 制造商:Texas Instruments 输入补偿电压:1.5 mV 共模抑制比（最小值）:95 dB 带宽:60 KHz 工作电源电压:3.3 V 电源电流:8 mA 工作温度范围:- 40 C to + 105 C 安装风格:SMD/SMT 封装 / 箱体:SOP-8 封装:Tube |
| HA9P2605-5 | 制造商:Rochester Electronics LLC 功能描述:- Bulk |
| HA9P2605-5 WAF | 制造商:Harris Corporation 功能描述: |
| HA9P2625-5 | 制造商:HARRIS 制造商全称:HARRIS 功能描述:Very Wideband, Uncompensated Operational Amplfiers |
| HA9P-2625-9 | 制造商:Rochester Electronics LLC 功能描述: |
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