参数资料
型号: IR3080MTR
厂商: International Rectifier
文件页数: 34/41页
文件大小: 0K
描述: IC PHASE CONTROLLER 32L MLPQ
标准包装: 3,000
系列: XPhase™
应用: 处理器
电流 - 电源: 11mA
电源电压: 9.5 V ~ 14 V
工作温度: 0°C ~ 100°C
安装类型: 表面贴装
封装/外壳: 32-VFQFN 裸露焊盘
供应商设备封装: 32-MLPQ(5x5)
包装: 带卷 (TR)
IR3080
The over temperature setting voltage of phases 1, 2, 5, and 6 is lower than the phase delay setting voltage,
VBIAS*RA PHASEx. Pre-select R PHASE11 =10k ? ,
R PHASEx 2 =
( RA PHASEx ? V BIAS ? V HOTSET ) * R PHASEx 1
V BIAS ? ( 1 ? RA PHASEx )
=
( 0 . 665 ? 6 . 8 ? 1 . 79 ) ? 10 * 10 3
6 . 8 ? ( 1 ? 0 . 665 )
= 12 . 1 k ?
R PHASEx 3 =
V HOTSET ? R PHASEx 1
V BIAS * ( 1 ? RA PHASEx )
=
1 . 79 ? 12 . 1 * 10 3
6 . 8 * ( 1 ? 0 . 665 )
= 7 . 87 k ?
R PHASE21 =10k ? , R PHASE22 =2.94k ? , R PHASE23 =4.64k ?
R PHASE51 =10k ? , R PHASE52 =2.32k ? , R PHASE53 =4.42k ?
R PHASE61 =10k ? , R PHASE62 =8.25k ? , R PHASE63 =6.49k ?
The over temperature setting voltage of Phases 3 and 4 is higher than the phase delay setting voltage,
VBIAS*RA PHASEx. Pre-select R PHASEX1 =10k ? ,
R PHASE 32 =
( V HOTSET ? RA PHASE 3 ? V BIAS ) ? R PHASE 31
V BIAS ? V HOTSET
=
( 1 . 79 ? 0 . 198 ? 6 . 8 ) ? 10 * 10 3
6 . 8 ? 1 . 79
= 887 ?
R PHASE 33 =
RA PHASE 3 ? V BIAS * R PHASE 31
V BIAS ? V HOTSET
=
0 . 198 ? 6 . 8 ? 10 * 10 3
6 . 8 ? 1 . 79
= 2 . 67 k ?
R PHASE41 =10k ? , R PHASE42 =768 ? , R PHASE43 =2.80k ?
Bootstrap Capacitor C BST
Choose C BST =0.1uF
Decoupling Capacitors for Phase IC and Power Stage
Choose C VCC =0.1uF, C VCCL =0.1uF
VOLTAGE LOOP COMPENSATION
Type III compensation is used for the converter with only ceramic output capacitors. The crossover frequency and
phase margin of the voltage loop can be estimated as follows.
f C 1 =
R DRP
2 π ? C E ? G CS ? R FB ? R LE
=
2 π ? ( 62 ? 22 * 10
? 6
576
) ? 34 ? 162 ? ( 0 . 5 * 10 ? 3 / 6 )
= 146 kHz
θ C 1 = 90 ? A tan( 0 . 5 ) ?
180
π
= 63 °
Choose R FB 1 =
2
3
? R FB =
2
3
? 162 = 110 ?
Choose the desired crossover frequency fc (=140kHz) around fc1 estimated above, and calculate
C FB =
1
4 π ? f C ? R FB 1
=
1
4 π ? 140 * 10 3 ? 110
= 5 . 2 nF , Choose C FB =5.6nF
C DRP =
( R FB + R FB 1 ) ? C FB
R DRP
=
( 162 + 110 ) ? 5 . 6 * 10 ? 9
576
= 2 . 7 nF
Page 34 of 41
9 /30/04
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