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| 型号： | IR3475MTR1PBF |
| 厂商： | International Rectifier |
| 文件页数： | 16/22页 |
| 文件大小： | 0K |
| 描述： | IC REG BUCK SYNC ADJ 10A PQFN |
| 产品培训模块： | SupIRBuck? Family and POL Design Tools Overview |
| 标准包装： | 750 |
| 系列： | SupIRBuck™ |
| 类型： | 降压（降压） |
| 输出类型： | 可调式 |
| 输出数： | 1 |
| 输出电压： | 0.5 V ~ 12 V |
| 输入电压： | 3 V ~ 27 V |
| 频率 - 开关： | 最高 750kHz |
| 电流 - 输出： | 10A |
| 同步整流器： | 是 |
| 工作温度： | -40°C ~ 125°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 16-VQFN 裸露焊盘 |
| 包装： | 带卷 (TR) |
| 供应商设备封装： | 16-QFN（4x5） |
10A ? Highly ? Integrated ? SupIRBuck TM ?
IR3475 ?
1.25 V ? ( 21 V - 1.25 V )
21 V ? 1.5 μ H ? 400k Hz
?
1 ? 1 A ?
1.25 V
21 V 3 ? 10 A ?
DESIGN?EXAMPLE?
?
DESIGN ? CRITERIA ??
? Input ? Voltage, ? VIN ? = ? 6V ? to ? 21V ?
? Output ? Voltage, ? VOUT ? = ? 1.25V ?
? Switching ? Frequency, ? Fs ? = ? 400kHz ?
? Inductor ? Ripple ? Current, ?? 2 Δ I ? = ? 2.5A ?
? Maximum ? Output ? Current, ? IOUT ? = ? 10A ?
? Over ? Current ? Trip, ? IOC ? = ? 15A ?
? Current ? Transient ? Step ? Size ? = ? 4A ?
? Overshoot ? Allowance, ? VOS ? = ? VOUT ? + ? 50mV ?
? Undershoot ? Allowance, ? VDROP ? = ? 50mV ?
loss ? as ? possible ? to ? increase ? the ? overall ? system ? efficiency. ??
For ? instance, ? choose ? a ? PIMB104T ‐ 1R5MS ‐ 39 ? manufactured ? by ?
CYNTEC. ? The ? inductance ? of ? this ? part ? is ? 1.5μH ? and ? has ? 3.8m Ω?
DCR. ? Ripple ? current ? needs ? to ? be ? recalculated ? using ? the ? chosen ?
inductor. ?
2 Δ I = = 2 A
Choose ? an ? input ? capacitor: ?
2
I IN_RMS = 10 A ? ? 1 + ? ? ? = 2 . 4 A
?
?
A ? Panasonic ? 10μF ? (ECJ3YB1E106M) ? accommodates ? 6 ? Arms ? of ?
Find ? R FF : ?
R FF =
1.25 V
1 V ? 20 pF ? 400k Hz
= 156 k Ω
ripple ? current ? at ? 300kHz. ? Due ? to ? the ? chemistry ? of ? multilayer ?
ceramic ? capacitors, ? the ? capacitance ? varies ? over ? temperature ?
and ? operating ? voltage, ? both ? AC ? and ? DC. ? One ? 10μF ? capacitor ? is ?
recommended. ?? In ? a ? practical ? solution, ? one ? 1μF ? capacitor ? is ?
required ? along ? with ? 10μF. ? The ? purpose ? of ? the ? 1μF ? capacitor ? is ?
Pick ? a ? standard ? value ? 158 ? k Ω , ? 1% ? resistor. ?
Find ? RSET: ?
to ? suppress ? the ? switching ? noise ? and ? deliver ? high ? frequency ?
current. ??
R SET =
13m Ω ? 15 A
1 9 μ A
= 1 0 .3k Ω
Choose ? an ? output ? capacitor: ?
To ? meet ? the ? undershoot ? and ? overshoot ? specification, ?
equations ? 7b ? and ? 8 ? will ? be ? used ? to ? calculate ? the ? minimum ?
Pick ? a ? 10.5k Ω , ? 1% ? standard ? resistor. ??
Find ? a ? resistive ? voltage ? divider ? for ? V OUT ? = ? 1.25V: ?
output ? capacitance. ? As ? a ? result, ? 190 μ F ? will ? be ? needed ? for ? 4A ?
load ? removal. ? To ? meet ? the ? stability ? requirement, ? choose ? an ?
output ? capacitor ? with ? ESR ? larger ? than ? 9m Ω . ? Combine ? those ?
V FB =
R 2
R 2 + R 1
? V OUT = 0.5 V
two ? requirements, ? one ? can ? choose ? a ? set ? of ? output ? capacitors ?
from ? manufactures ? such ? as ? SP ‐ Cap ? (Specialty ? Polymer ?
Capacitor) ? from ? Panasonic ? or ? POSCAP ? from ? Sanyo. ? A ? 220 μ F ?
R 2 ? = ? 1.33k Ω , ? R 1 ? = ? 1.96 ? k Ω , ? both ? 1% ? standard ? resistors. ??
Choose ? the ? soft ? start ? capacitor: ?
Once ? the ? soft ? start ? time ? has ? chosen, ? such ? as ? 1000μs ? to ?
reach ? to ? the ? reference ? voltage, ? a ? 22nF ? for ? C SS ? is ? used ? to ?
meet ? 1000μs. ?
Choose ? an ? inductor ? to ? meet ? the ? design ? specification: ?
(4TPE220MIC2) ? from ? Sanyo ? with ? 18m Ω? ESR ? will ? meet ? both ?
requirements. ?
If ? an ? all ? ceramic ? output ? capacitor ? solution ? is ? desired, ? the ?
external ? slope ? injection ? circuit ? composed ? of ? R6, ? C13, ? and ? C14 ?
is ? required ? as ? explained ? in ? the ? Stability ? Considerations ?
section. ? In ? this ? design ? example, ? we ? can ? choose ? C14 ? = ? 1nF ? and ?
C13 ? = ? 100nF. ? To ? calculate ? the ? value ? of ? R6 ? with ? PIMB104T ‐
1R5MS ‐ 39 ? as ? our ? inductor: ?
V OUT ? ( V IN ? V OUT )
1.25 V ? ( 21 V - 1.25 V )
R 6 =
1 . 5 μ H
?
?
L =
V IN ? 2 Δ I ? F s
=
21 V ? 2.5 A ? 400k Hz
= 1.18 μ H
?
?
?
?
?
L
DCR ? C 13
=
3 . 8 m Ω ? 100 nF
= 3 . 95 k Ω
?
Choose ? the ? inductor ? with ? the ? lowest ? DCR ? and ? AC ? power ?
Pick ? a ? standard ? value ? for ? R6 ? = ? 3.92k Ω . ?
16
March ? 27, ? 2013 ?? | ?? V2.2 ?? | ?? PD97602
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相关代理商/技术参数 |
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|---|---|
| IR3475MTRPBF | 功能描述:直流/直流开关调节器 10A SupIRBuck Reg 750kHz, 3.0-27V in RoHS:否 制造商:International Rectifier 最大输入电压:21 V 开关频率:1.5 MHz 输出电压:0.5 V to 0.86 V 输出电流:4 A 输出端数量: 最大工作温度: 安装风格:SMD/SMT 封装 / 箱体:PQFN 4 x 5 |
| IR3476 | 制造商:IRF 制造商全称:International Rectifier 功能描述:12A Highly Integrated SupIRBuck IR3476 TM |
| IR3476_13 | 制造商:IRF 制造商全称:International Rectifier 功能描述:12A Highly Integrated SupIRBuck Continuous 12A Load Capability |
| IR3476MPBF | 制造商:International Rectifier 功能描述:BUCK SYNC ADJ 12A PQFN 制造商:International Rectifier 功能描述:BUCK, SYNC, ADJ, 12A, PQFN 制造商:International Rectifier 功能描述:BUCK, SYNC, ADJ, 12A, PQFN; Primary Input Voltage:27V; No. of Outputs:1; Output Voltage:12V; Output Current:12A; Voltage Regulator Case Style:QFN; No. of Pins:17; Operating Temperature Min:-40C; Operating Temperature Max:125C; ;RoHS Compliant: Yes |
| IR3476MTR1PBF | 功能描述:直流/直流开关调节器 12A SupIRBuck Reg 750kHz, 3.0-27V in RoHS:否 制造商:International Rectifier 最大输入电压:21 V 开关频率:1.5 MHz 输出电压:0.5 V to 0.86 V 输出电流:4 A 输出端数量: 最大工作温度: 安装风格:SMD/SMT 封装 / 箱体:PQFN 4 x 5 |
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