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参数资料
| 型号： | IRDC3822A |
| 厂商： | International Rectifier |
| 文件页数： | 15/21页 |
| 文件大小： | 0K |
| 描述： | BOARD EVAL SYNC BUCK CONVERTER |
| 产品变化通告： | (EP) Parts Discontinuation 25/May/2012 |
| 标准包装： | 1 |
| 系列： | * |
PD-60345
IR3822AMPbF
Based on the frequency of the zero generated by
output capacitor and its ESR versus crossover
frequency, the compensation type can be
different. The table below shows the
compensation types and location of crossover
frequency.
Select crossover frequency:
F o < F ESR and F o ≤ ( 1/5 ~ 1/10 ) * F s
Fo=60kHz
Since: FLC<Fo<Fs/2<FESR , type III method B is
selected to place the poles and zeros.
Compensator
type
Type II(PI)
Type III(PID)
Method A
Type III(PID)
Method B
F ESR vs. F o
F LC <F ESR <F o <F s/2
F LC <F o <F ESR <F s/2
F LC <F o <F s/2 <F ESR
Output
capacitor
Electrolytic
, Tantalum
Tantalum,
ceramic
Ceramic
The following design rules will give a crossover
frequency approximately one-tenth of the
switching frequency. The higher the band width,
the potentially faster the load transient response.
The DC gain will be large enough to provide high
DC-regulation accuracy (typically -5dB to -12dB).
The phase margin should be greater than 45 o for
overall stability.
Table1- The compensation type and location
of F ESR versus F o
Desired Phase Boost: Θ max = 70 o
The details of these compensation types are
discussed in application note AN-1043 which can
F Z 2 = F o *
1 - Sin Θ
1 + Sin Θ
F P 2 = F o *
be downloaded from IR’s website at www.irf.com.
For this design we have:
V in =12V
V o =1.8V
V osc =1.25V
V ref =0.6V
g m =1000umoh
L o =2.2uH
C o =6x22uF, ESR=0.5mOhm
F Z 2 = 10 . 58 kHz
1 + Sin Θ
1 - Sin Θ
F P 2 = 340 . 28 kHz
Select : F Z1 = 0 . 5 * F Z 2 and F P3 = 0.5 * F s
Select : C 7 = 180pF
2 π * F o * L o * C o * V OSC
F s =300kHz
The value of the capacitance used in the
compensator design must be the small signal
value. For instance, the small signal capacitance
of the 22uF capacitor used in this design is 12uF
at 1.8 VDC bias and 600 kHz frequency. It is this
R 3 =
C 7 * V in
Select : R 3 = 34.8K Ω
Calculate C 4 and C 3 :
, R 3 = 34 . 56 K ? , check R 3 ≥
2
g m
value that must be used for all computations
related to the compensation. The small signal
value may be obtained from the manufacturer’s
datasheets, design tools or SPICE models.
Alternatively, they may also be inferred from
C 4 =
C 3 =
1
2 π * F Z1 * R 3
1
2 π * F P 3 * R 3
; C 4 = 0.86nF, Select : C 4 = 1 . 0 nF
; C 3 = 30 . 8 pF , Select : C 3 = 22 pF
measuring the power stage transfer function of
the converter and measuring the double pole
Calculate R 10 , R 8 and R 9 :
frequency FLC and using equation (11) to
compute the small signal Co.
R 10 =
1
2 π * C 7 * F P 2
; R 10 = 2 . 60 K Ω , check R 10 ≥
1
g m
R 8 =
- R 10 ; R 8 = 80 . 97 K Ω , Select : R 8 = 80 . 6 K Ω
R 9 =
* R 8 ; R 9 = 40 . 30 K Ω , Select : R 9 = 40 . 2 K Ω
These result to:
F LC =12.65kHz
F ESR =4.4MHz
F s/2 =150kHz
11/04/08
Select : R 10 = 2 . 61 K Ω
1
2 π * C 7 * F Z 2
V ref
V o - V ref
15
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