参数资料
型号: IRDC3843A
厂商: International Rectifier
文件页数: 23/33页
文件大小: 0K
描述: BOARD EVAL SUPIRBUCK IR3843A
产品培训模块: SupIRBuck? Family and POL Design Tools Overview
标准包装: 1
系列: SupIRBuck™
主要目的: DC/DC,步降
输出及类型: 1,非隔离
输出电压: 1.8V
电流 - 输出: 3A
输入电压: 12V
稳压器拓扑结构: 降压
频率 - 开关: 600kHz
板类型: 完全填充
已供物品:
已用 IC / 零件: IR3843A
PD-97509
IR3843AMPbF
F Z 2 = F o
= 14.11 kHz
F P 2 = F o
= 453.7 kHz
R OCSet ? I OCSet
Detailed calculation of compensation TypeIII
Desired Phase Margin Θ = 70 o
1 ? sin Θ
1 + sin Θ
1 + sin Θ
1 ? sin Θ
Select : F Z 1 = 0 . 5 * F Z 2 = 7.05 kHz and
F P 3 = 0.5 * F s = 300 kHz
Select : C 7 = 2.2 nF
Calculate R 3 , C 3 and C 4 :
Programming the Current-Limit
The Current-Limit threshold can be set by
connecting a resistor (R OCSET ) from the SW pin
to the OCSet pin. The resistor can be calculated
by using equation (4). This resistor R OCSET must
be placed close to the IC.
The R DS(on) has a positive temperature
coefficient and it should be considered for the
worst case operation.
)
I SET = I L ( critical = .......... .......... (32)
R DS ( on )
R DS ( on ) = 24.5 m Ω * 1.25 = 30.625 m Ω
I SET ? I o ( LIM ) = 3A * 1.5 = 4 . 5 A
(50% over nominal output current )
I OCSet = 59.07 μ A (at F s = 600 kHz)
R OCSet = 2.33 k Ω Select R 7 = 2.26 k Ω
R 3 =
2 π * F o * L o * C o * V osc
C 7 * V in
; R 3 = 2.71 k Ω
Setting the Power Good Threshold
A window comparator internally sets a lower
Power Good threshold at 0.6V and an upper
Power Good threshold at 0.8V. When the voltage
Select : R 3 = 2 . 74 k Ω
at the FB pin is within the window set by these
thresholds, PGood is asserted.
C 4 =
C 3 =
1
2 π * F Z 1 * R 3
1
2 π * F P 3 * R 3
; C 4 = 8 . 24 nF, Select : C 4 = 8 . 2 nF
; C 3 = 193.62 pF , Select : C 3 = 180 pF
The PGood is an open drain output. Hence, it is
necessary to use a pull up resistor R PG from
PGood pin to Vcc. The value of the pull-up
resistor must be chosen such as to limit the
current flowing into the PGood pin, when the
output voltage is not in regulation, to less than 5
mA. A typical value used is 10k ? .
Calculate R 10 , R 8 and R 9 :
R 10 =
R 8 =
1
2 π * C 7 * F P 2
1
2 π * C 7 * F Z 2
; R 10 = 160 Ω , Select : R 10 = 158 Ω
- R 10 ; R 8 = 5 k Ω ,
Select : R 8 = 4.99 k Ω
R 9 =
V ref
V o - V ref
* R 8 ; R 9 = 3.18 k Ω Select : R 9 = 3.16 k Ω
Rev 16.0
23
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