参数资料
型号: LM4870MX
厂商: NATIONAL SEMICONDUCTOR CORP
元件分类: 音频/视频放大
英文描述: 1.1 W, 1 CHANNEL, AUDIO AMPLIFIER, PDSO16
封装: SOIC-16
文件页数: 9/11页
文件大小: 283K
代理商: LM4870MX
Application Information (Continued)
are required for 1.0W of output power. Since 5V rails are
common, it is chosen to be the supply voltage. Supply volt-
age (up to a maximum of 5.5V) above the required 4.6V will
allow the LM4870 to reproduce transient signals at greater
than 1.0W of output power. The extra voltage will also in-
crease the device power dissipation, so the designer must
make sure that the conditions explained in the Power Dissi-
pationsection are not violated.
Once the power dissipation issues have been addressed,
the required differential gain can be determined from Equa-
tion 4:
From equation 4, the minimum A
vd is A vd = 2.83; use Avd=
3.
Since the amplifier output is bridged, giving a gain of 2, and
the desired system gain is 3, the ratio of feedback (R
f)toin-
put (R
i) resistor is 1.5:1. If Ri is set to the required input im-
pedance of 20 k
, then R
f =30 k. The final design step is
to address the bandwidth requirements which must be
stated as a pair of 3 dB frequency points. Five times away
from a 3 dB point is 0.17 dB down from passband response
which is better than the required ±0.25 dB specified.
f
L = 100 Hz/5 = 20 Hz
f
H = 20 kHz∏5 = 100 HzAs stated in the External Com-
ponents section, R
i in conjunction with Ci create a high-
pass filter.
C
i ≥ 1/(2π * 20 k * 20 Hz) = 0.397 F;
use 0.39 F.
The high frequency pole is determined by the product of the
desired high frequency pole, f
H, and the differential gain, A
vd
. With a A
vd = 3 and fH = 100 kHz, the resulting GBWP =
150 kHz which is much smaller than the LM4870 GBWP of
4 MHz. This figure displays that if a designer has a need to
design an amplifier with a higher differential gain, the
LM4870 can still be used without running into bandwidth
problems.
LM4870
www.national.com
7
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