参数资料
型号: LM4880MDA
厂商: NATIONAL SEMICONDUCTOR CORP
元件分类: 音频/视频放大
英文描述: 0.325 W, 2 CHANNEL, AUDIO AMPLIFIER, UUC
封装: DIE
文件页数: 2/15页
文件大小: 418K
代理商: LM4880MDA
Application Information (Continued)
(4)
A
V =RF/Ri
(5)
From
Equation (4), the minimum gain is::
A
V = 1.26
Since the desired input impedance was 20 k
, and with a
gain of 1.26, a value of 27 k
is designated for R
f, assum-
ing 5% tolerance resistors. This combination results in a
nominal gain of 1.35. The final design step is to address the
bandwidth requirements which must be stated as a pair of
3 dB frequency points. Five times away from a 3 dB point
is 0.17 dB down from passband response assuming a single
pole roll-off. As stated in the External Components section,
both R
i in conjunction with Ci, and Co with RL, create first or-
der high pass filters. Thus to obtain the desired frequency
low response of 100 Hz within ± 0.5 dB, both poles must be
taken into consideration. The combination of two single order
filters at the same frequency forms a second order response.
This results in a signal which is down 0.34 dB at five times
away from the single order filter 3 dB point. Thus, a fre-
quency of 20 Hz is used in the following equations to ensure
that the response if better than 0.5 dB down at 100 Hz.
C
i ≥ 1/(2π*20k*20Hz) = 0.397 F; use 0.39 F
C
o ≥ 1/(2π*8*20Hz) = 995 F; use 1000 F
The high frequency pole is determined by the product of the
desired high frequency pole, f
H, and the closed-loop gain,
A
V. With a closed-loop gain magnitude of 1.35 and fH = 100
kHz, the resulting GBWP = 135 kHz which is much smaller
than the LM4880 GBWP of 12.5 MHz. This figure displays
that if a designer has a need top design an amplifier with a
higher gain, the LM4880 can still be used without running
into bandwidth limitations.
LM4880
www.national.com
10
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