参数资料
型号: LT1107CS8-5#TRPBF
厂商: Linear Technology
文件页数: 8/16页
文件大小: 0K
描述: IC REG BUCK BST INV 5V .4A 8SOIC
标准包装: 2,500
类型: 降压(降压),升压(升压),反相
输出类型: 固定
输出数: 1
输出电压: 5V
输入电压: 2 V ~ 30 V
频率 - 开关: 63kHz
电流 - 输出: 400mA
同步整流器:
工作温度: 0°C ~ 70°C
安装类型: 表面贴装
封装/外壳: 8-SOIC(0.154",3.90mm 宽)
包装: 带卷 (TR)
供应商设备封装: 8-SOIC
LT1107
A PPLICATI
S I FOR ATIO
()
? ? R ′ t ?
? 1 ? e
?
t =
I L ( 15 )
R ′ ? ?
where DC = duty cycle (0.50 in step-down mode)
V SW = switch drop in step-down mode
V D = diode drop (0.5V for a 1N5818)
I OUT = output current
V OUT = output voltage
V IN = minimum input voltage
V SW is actually a function of switch current which is in turn
a function of V IN , L, time, and V OUT . To simplify, 1.5V can
be used for V SW as a very conservative value.
Once I PEAK is known, inductor value can be derived from:
In this mode the switch is arranged in common collector
or step-down mode. The switch drop can be modeled as
a 0.75V source in series with a 0.65 ? resistor. When the
switch closes, current in the inductor builds according to:
V L
L
? ?
where R ′ = 0.65 ? + DCR L
V L = V IN – 0.75V
As an example, suppose –5V at 50mA is to be generated
V IN ( MIN ) ? V SW OUT
L =
I PEAK
? V
× t ON
( 11 )
from a 4.5V to 5.5V input. Recalling Equation (14),
P L = ( ? 5 V + 0 . 5 V ) ( 50 mA ) = 275mW
(16 )
where t ON = switch ON time (7 μ s).
Energy required from the inductor is:
= = 4 . 4 μ J
Next, the current limit resistor R LIM is selected to give
I PEAK from the Maximum Switch Current vs R LIM curve.
The addition of this resistor keeps maximum switch cur-
P L
f OSC
275 mW
63 kHz
( 17 )
rent constant as the input voltage is increased.
Picking an inductor value of 100 μ H with 0.2 ? DCR results
2 ( 300 mA ) ? 5 + 0 . 5 ?
? ? 12 ? 1 . 5 + 0 . 5 ? ?
( 4 . 5 V ? 0 . 75 V )
(
)
? 1 ? e
As an example, suppose 5V at 300mA is to be generated
from a 12V to 24V input. Recalling Equation (10):
I PEAK = ? ? = 600 mA ( 12 )
0 . 50
in a peak switch current of:
I PEAK =
0 . 65 ? + 0 . 2 ?
= 325 mA
?
?
?
? 0.85 ? ? 9 μ s ?
100 μ H ?
?
?
( 18 )
Next, inductor value is calculated using Equation (11):
Substituting I PEAK into Equation (04) results in:
L =
12 ? 1.5 ? 5
600 mA
7 μ s = 64 μ H
( 13 )
E L =
1
2
( 100 μ H )( 0 . 325 A
) 2 = 5 . 28 μ J
( 19 )
Use the next lowest standard value (56 μ H).
Then pick R LIM from the curve. For I PEAK = 600mA, R LIM
= 56 ? .
Inductor Selection –– Positive-to-Negative Converter
Figure 4 shows hookup for positive-to-negative conver-
sion. All of the output power must come from the inductor.
In this case,
Since 5.28 μ J > 3.82 μ J, the 100 μ H inductor will work.
With this relatively small input range, R LIM is not usually
necessary and the I LIM pin can be tied directly to V IN . As in
the step-down case, peak switch current should be limited
to ~650mA.
Step-Up (Boost Mode) Operation
A step-up DC/DC converter delivers an output voltage
P L = ( V OUT D ) ( OUT )
+ V I
(14)
higher than the input voltage. Step-up converters are not
short-circuit protected since there is a DC path from input
to output.
1107fa
8
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