参数资料
型号: MAX15003ATM+
厂商: Maxim Integrated Products
文件页数: 23/31页
文件大小: 0K
描述: IC REG CTRLR BUCK PWM 48TQFN-EP
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 43
PWM 型: 电压模式
输出数: 3
频率 - 最大: 2.2MHz
电源电压: 5.5 V ~ 23 V
降压:
升压:
回扫:
反相:
倍增器:
除法器:
Cuk:
隔离:
工作温度: -40°C ~ 125°C
封装/外壳: 48-WFQFN 裸露焊盘
包装: 管件
MAX15003
Triple-Output Buck Controller with
Tracking/Sequencing
Type II: Compensation When f CO > f ZERO, ESR
1) Calculate the f ZERO,ESR and LC double pole, f LC :
V OUT
f ZERO , ESR =
1
2 π × ESR × COUT
R 1
f LC =
1
2 π × L × COUT
-
g M
COMP
2) Calculate the unity-gain crossover frequency as:
f CO ≤ SW
R 2
V REF
+
R F
C F
C CF
f
10
3) Determine R F from the following:
( 2 π × fCO × L ) VOUT
R F = RAMP
Figure 6a. Type II Compensation Network
GAIN
(dB)
V
VFB × VIN × gm × ESR
Note: R F is derived by setting the total loop gain at
crossover frequency to unity, e.g., G EA (f CO ) x G M (f CO )
= 1V/V. The transconductance error amplifier gain is
G EA (f CO ) = g M x R F while the modulator gain is:
G MOD ( f CO ) =
VIN
VRAMP
×
ESR
2 π × fCO × L
×
VFB
VOUT
The total loop gain can be expressed logarithmically as
1ST ASYMPTOTE
G MOD V REF V OUT-1 ( ω C F ) -1
follows:
2 0log10 [ gmRF ] +
ESR × VIN × VFB
? ? ( 2 π × fCO × L ) × VOUT × VRAMP ? ?
2ND ASYMPTOTE
G MOD V REF V OUT-1 R F
3RD ASYMPTOTE
G MOD V REF V OUT-1 ( ω C CF ) -1
? ?
2 0log10 ? ? = 0 dB
1ST POLE
(AT ORIGIN)
1ST ZERO
(R F C F ) -1
2ND POLE
(R F C CF ) -1
ω (rad/s)
where V RAMP is the peak-to-peak ramp amplitude
equal to 2V.
4) Place a zero at or below the LC double pole, f LC :
Figure 6b. Type II Compensation Network Response
C F =
1
2 π × RF × fLC
C CF =
When the f ZERO,ESR is lower than f CO and close to f LC ,
a Type II compensation network provides the neces-
sary closed-loop response. The Type II compensation
network provides a mid-band compensating zero and
high-frequency pole (see Figures 6a and 6b).
R F C F provides the mid-band zero f MID,ZERO , and
R F C CF provides the high-frequency pole. Use the fol-
lowing procedure to calculate the compensation net-
5) Place a high-frequency pole at or below f P = 0.5 x
f SW :
1
π × RF × fSW
6) Choose an appropriately sized R1 (connected from
OUT_ to FB_, start with a 10k ? ). Once R1 is select-
ed, calculate R2 using the following equation:
FB
work components.
Maxim Integrated
R 2 = R 1 ×
where V FB = 0.6V.
V
VOUT ? VFB
23
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