参数资料
型号: MAX16838AUP+
厂商: Maxim Integrated
文件页数: 15/21页
文件大小: 0K
描述: IC LED DRIVR HIGH BRIGHT 20TSSOP
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 74
恒定电流:
拓扑: 线性(LDO),PWM,SEPIC,递升(升压)
输出数: 2
内部驱动器:
类型 - 主要: 车载,背光
类型 - 次要: 高亮度 LED(HBLED)
频率: 200kHz ~ 2MHz
电源电压: 4.75 V ~ 40 V,4.55 V ~ 5.5 V
输出电压: 4.75 V ~ 5.25 V
安装类型: 表面贴装
封装/外壳: 20-TSSOP(0.173",4.40mm 宽)裸露焊盘
供应商设备封装: 20-TSSOP-EP
包装: 管件
工作温度: -40°C ~ 125°C
MAX16838
Integrated, 2-Channel, High-Brightness LED Driver
with High-Voltage Boost and SEPIC Controller
Enable (EN)
EN is a logic input that completely shuts down the
device when connected to logic-low, reducing the
current consumption of the device to less than 15 F A
(typ). The logic threshold at EN is 1.24V (typ). The volt-
age at EN must exceed 1.24V before any operation can
commence. There is a 71mV hysteresis on EN. The EN
input also allows programming the supply input UVLO
threshold using an external voltage-divider to sense the
MAX16838
1.24V
EN
V IN
R1 EN
R2 EN
input voltage, as shown in Figure 3. Use the following
V ON
equation to calculate the value of R1 EN and R2 EN in
Figure 3:
? ?
R1 EN
= ? ? 1 ? × R2 EN
? V UVLOIN ?
where V UVLOIN is the EN rising threshold (1.24V) and
V ON is the desired input startup voltage. Choose an
R2 EN between 10k I and 50k I . Connect EN to IN if not
used.
Current Foldback
The MAX16838 includes a current-foldback feature to
limit the input current at low V IN . Connect a resistor-
divider between IN, CFB, and SGND to set the current-
foldback threshold. When the voltage at CFB goes below
1.23V, then the LED current starts reducing proportion-
ally to V CFB .
This feature can also be used for analog dimming of the
LEDs. Connect CFB to V CC to disable this feature.
Applications Information
Boost-Circuit Design
First, determine the required input supply voltage range,
the maximum voltage needed to drive the LED strings
including the minimum 1V across the constant LED
current sink (V LED ), and the total output current needed
to drive the LED strings (I LED ).
Calculate the maximum duty cycle (D MAX ) using the
following equation:
D MAX = (V LED + V D – V IN_MIN )/(V LED + V D )
where V D is the forward drop of the rectifier diode,
V IN_MIN is the minimum input supply voltage, and
V LED is the output voltage. Select the switching
frequency (f SW ) depending on the space, noise, dynam-
ic response, and efficiency constraints.
Maxim Integrated
Figure 3. Setting the MAX16838 Undervoltage Lockout
Threshold
Inductor Selection in Boost Configuration
Select the maximum peak-to-peak ripple on the inductor
current (IL P-P ). Use the following equations to calculate
the maximum average inductor current (IL AVG ) and
peak inductor current (IL PEAK ):
IL AVG = I LED /(1 - D MAX )
Assuming IL P-P is 40% of the average inductor current:
IL P-P = IL AVG x 0.4
IL PEAK = IL AVG + IL P-P /2
Calculate the minimum inductance value L MIN with the
inductor current ripple set to the maximum value:
L MIN = V IN_MIN x D MAX /(f SW x IL P-P )
Choose an inductor that has a minimum inductance
greater than the calculated L MIN and current rating
greater than IL PEAK . The recommended saturation
current limit of the selected inductor is 10% higher than
the inductor peak current. The IL P-P can be chosen
to have a higher ripple than 40%. Adjust the minimum
value of the inductance according to the chosen ripple.
One fact that must be noted is that the slope compensa-
tion is fixed and has a 120mV peak per switching cycle.
The dv/dt of the slope compensation ramp is 120f SW V/
F s, where f SW is in kHz. After selecting the inductance
it is necessary to verify that the slope compensation is
adequate to prevent subharmonic oscillations. In the
case of the boost, the following criteria must be satisfied:
120f SW > R CS (V LED - 2V IN_MIN )/2L
where L is the inductance value in F H, R CS is the
current-sense resistor value in ω, V IN_MIN is the mini-
mum input voltage in V, V LED is the output voltage, and
f SW is the switching frequency in kHz.
If the inductance value is chosen to keep the inductor
in discontinuous conduction mode, the equation above
does not need to be satisfied.
15
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