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| 型号： | MAX1847EEE+T |
| 厂商： | Maxim Integrated Products |
| 文件页数： | 13/20页 |
| 文件大小： | 0K |
| 描述： | IC REG CTRLR FLYBK INV CM 16QSOP |
| 产品培训模块： | Lead (SnPb) Finish for COTS Obsolescence Mitigation Program |
| 标准包装： | 2,500 |
| PWM 型： | 电流模式 |
| 输出数： | 1 |
| 频率 - 最大： | 345kHz |
| 占空比： | 98% |
| 电源电压： | 3 V ~ 16.5 V |
| 降压： | 无 |
| 升压： | 无 |
| 回扫： | 是 |
| 反相： | 是 |
| 倍增器： | 无 |
| 除法器： | 无 |
| Cuk： | 无 |
| 隔离： | 无 |
| 工作温度： | -40°C ~ 85°C |
| 封装/外壳： | 16-SSOP（0.154"，3.90mm 宽） |
| 包装： | 带卷 (TR) |
High-Efficiency, Current-Mode,
Inverting PWM Controller
2)
3)
4)
5)
Higher frequencies allow the use of smaller value
(hence smaller size) inductors and capacitors.
Higher frequencies consume more operating
power both to operate the IC and to charge and
discharge the gate at the external FET, which
tends to reduce the efficiency at light loads.
Higher frequencies may exhibit lower overall effi-
ciency due to more transition losses in the FET;
however, this shortcoming can often be nullified
by trading some of the inductor and capacitor size
benefits for lower-resistance components.
High-duty-cycle applications may require lower
frequencies to accommodate the controller mini-
mum off-time of 0.4μs. Calculate the maximum
oscillator frequency with the following formula:
returned to the rate set by R FREQ . Choose R FREQ such
that f OSC = 0.9 x f SYNC .
Choosing Inductance Value
The inductance value determines the operation of the
current-mode regulator. Except for low-current applica-
tions, most circuits are more efficient and economical
operating in continuous mode, which refers to continu-
ous current in the inductor. In continuous mode there is
a trade-off between efficiency and transient response.
Higher inductance means lower inductor ripple current,
lower peak current, lower switching losses, and, there-
fore, higher efficiency. Lower inductance means higher
inductor ripple current and faster transient response. A
reasonable compromise is to choose the ratio of induc-
tor ripple current to average continuous current at mini-
mum duty cycle to be 0.4. Calculate the inductor ripple
( V IN ( MAX ) ? V SW LIM )
f OSC ( MAX ) =
×
V IN ( MIN ) ? V SW ? V LIM
1
t OFF ( MIN )
V IN ( MIN ) ? V SW ? V LIM ? V OUT + V D
with the following formula:
I RIPPLE =
0 . 4 × I LOAD ( MAX ) × ( V IN ( MAX ) ? V SW ? V LIM ? V OUT + V D
? V
)
Remember that V OUT is negative when using this formula.
When running at the maximum oscillator frequency
(f OSCILLATOR ) and maximum duty cycle (D MAX ), do not
exceed the minimum value of D MAX stated in the
Electrical Characteristics table. For designs that
exceed the D MAX and f OSC(MAX) , an autotransformer
can reduce the duty cycle and allow higher operating
frequencies.
The oscillator frequency is set by a resistor, RFREQ,
which is connected from FREQ to GND. The relation-
ship between fOSC (in Hz) and RFREQ (in ? ) is slightly
nonlinear, as illustrated in the Typical Operating
Characteristics. Choose the resistor value from the
graph and check the oscillator frequency using the fol-
Then calculate an inductance value:
L = (V IN(MAX) / I RIPPLE ) x (D MIN / f OSC )
Choose the closest standard value. Once again, remem-
ber that V OUT is negative when using this formula.
Determining Peak Inductor Current
The peak inductor current required for a particular out-
put is:
I LPEAK = I LDC + (I LPP / 2)
where I LDC is the average DC inductor current and I LPP
is the inductor peak-to-peak ripple current. The I LDC
and I LPP terms are determined as follows:
f OSC =
( ) ( ) ( )
? 5 . 21 × 10 ? 7 + 1 . 92 × 10 ? 11 × R FREQ × ( R FREQ ) ?
? 19
? 4 . 86 × 10
lowing formula:
?? ??
1
2
I LDC =
I LPP =
I LOAD
( 1 ? D MAX )
( V IN ( MIN ) ? V SW ? V LIM
L x f OSC
) xD
MAX
External Synchronization (MAX1847 only)
The SYNC input provides external-clock synchroniza-
tion (if desired). When SYNC is driven with an external
clock, the frequency of the clock directly sets the
MAX1847’s switching frequency. A rising clock edge
on SYNC is interpreted as a synchronization input. If
the sync signal is lost, the internal oscillator takes over
at the end of the last cycle, and the frequency is
where L is the selected inductance value. The satura-
tion rating of the selected inductor should meet or
exceed the calculated value for I LPEAK , although most
coil types can be operated up to 20% over their satura-
tion rating without difficulty. In addition to the saturation
criteria, the inductor should have as low a series resis-
______________________________________________________________________________________
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