参数资料
型号: MAX5080EVKIT
厂商: Maxim Integrated Products
文件页数: 14/19页
文件大小: 0K
描述: EVAL KIT FOR MAX5080
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 1
主要目的: DC/DC,步降
输出及类型: 1,非隔离
输出电压: 3.3V
电流 - 输出: 1A
输入电压: 4.5 ~ 40 V
稳压器拓扑结构: 降压
频率 - 开关: 250kHz
板类型: 完全填充
已供物品:
已用 IC / 零件: MAX5080
1A, 40V, MAXPower Step-Down
DC-DC Converters
C8
R 6 =
1
2 π × C 6 × 0 . 5 × f SW
C6
R6
R5
C7
Since R3 >> R6, R3 + R6 can be approximated as R3.
R3 is then calculated as:
R3
V OUT
R4
REF
EA
COMP
R 3 ≈
1
2 π × f LC × C 6
f P3 is set at 5xf C . Therefore C8 is calculated as:
GAIN
(dB)
CLOSED-LOOP
GAIN
EA
C 8 =
C 7
( 2 π × C 7 × R 5 × f P3 ? 1 )
GAIN
Compensation When f C > f ZESR
For larger ESR capacitors such as tantalum and alu-
minum electrolytic ones, f ZESR can occur before f C . If
f Z1 f Z2
f C
f P2 f P3
FREQUENCY
f ZESR < f C , then f C occurs between f P2 and f P3 . f Z1 and
f Z2 remain the same as before however, f P2 is now set
equal to f ZESR . The output capacitor’s ESR zero fre-
Figure 3. Error Amplifier Compensation Circuit (Closed-Loop
and Error-Amplifier Gain Plot) for Ceramic Capacitors
Pick a value for the feedback resistor R5 in Figure 3
(values between 1k ? and 10k ? are adequate).
C7 is then calculated as:
quency is higher than f LC but lower than the closed-
loop crossover frequency. The equations that define
the error amplifier’s poles and zeroes (f Z1 , f Z2 , f P1 , f P2 ,
and f P3 ) are the same as before. However, f P2 is now
lower than the closed-loop crossover frequency. Figure
4 shows the error amplifier feedback as well as its gain
response for circuits that use higher-ESR output capac-
itors (tantalum or aluminum electrolytic).
C 7 =
1
2 π × 0 . 8 × f LC × R 5
Pick a value for the feedback resistor R5 in Figure 4 (val-
ues between 1k ? and 10k ? are adequate).
f C occurs between f Z2 and f P2 . The error-amplifier gain
C7 is then calculated as:
(G EA ) at f C is due primarily to C6 and R5. Therefore,
G EA(fC) = 2 π x f C x C6 x R5 and the modulator gain at
f C is:
C 7 =
1
2 π × 0 . 8 × f LC × R 5
G MOD(fC) =
G MOD(DC)
( 2 π ) 2 × L × C OUT × f C 2
The error amplifier gain between f P2 and f P3 is approxi-
mately equal to R5/R6 (given that R6 << R3). R6 can
then be calculated as:
R 5 × G MOD(DC)
Since G EA(fC) x G MOD(fC) = 1, C6 is calculated by:
f C × L × C OUT × 2 π
C 6 =
R 5 × 10 × f LC 2
R 6 ≈
f C 2
C6 is then calculated as:
f P2 is set at 1/2 the switching frequency (f SW ). R6 is
then calculated by:
C 6 =
C OUT × ESR
R 6
14
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MAX5081ATE+ 功能描述:直流/直流开关转换器 1A 40V MAXPower Step-Down RoHS:否 制造商:STMicroelectronics 最大输入电压:4.5 V 开关频率:1.5 MHz 输出电压:4.6 V 输出电流:250 mA 输出端数量:2 最大工作温度:+ 85 C 安装风格:SMD/SMT
MAX5081ATE+T 功能描述:直流/直流开关转换器 1A 40V MAXPower Step-Down RoHS:否 制造商:STMicroelectronics 最大输入电压:4.5 V 开关频率:1.5 MHz 输出电压:4.6 V 输出电流:250 mA 输出端数量:2 最大工作温度:+ 85 C 安装风格:SMD/SMT
MAX5081ATE-T 功能描述:直流/直流开关转换器 1A 40V MAXPower Step-Down RoHS:否 制造商:STMicroelectronics 最大输入电压:4.5 V 开关频率:1.5 MHz 输出电压:4.6 V 输出电流:250 mA 输出端数量:2 最大工作温度:+ 85 C 安装风格:SMD/SMT
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