参数资料
型号: MAX8765ETI+T
厂商: Maxim Integrated Products
文件页数: 22/30页
文件大小: 0K
描述: IC CHARGER BATTERY 28-TQFN
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 2,500
功能: 充电管理
电池化学: 多化学
电源电压: 8 V ~ 28 V
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 28-WFQFN 裸露焊盘
供应商设备封装: 28-TQFN-EP(5x5)
包装: 带卷 (TR)
MAX1908/MAX8724/MAX8765/MAX8765A
Low-Cost Multichemistry Battery Chargers
where R L varies with load according to R L = V BATT /I CHG.
Output zero due to output capacitor ESR:
GM OUT
BATT
f Z _ ESR =
1
2 π R ESR × C OUT
R ESR
R L
The loop transfer function is given by:
CCV
R CV
R OGMV
GMV
REF
C OUT
LTF = GM OUT × R L × GMV × R OGMV ×
( 1 + sC OUT × R ESR )( 1 + sC CV × R CV )
( 1 + sC CV × R OGMV ) ( 1 + sC OUT × R L )
C CV
Assuming the compensation pole is a very low
frequency, and the output zero is a much higher fre-
quency, the crossover frequency is given by:
Figure 5. CCV Loop Diagram
f CO _ CV =
GMV × R CV × GM OUT
2 π C OUT
GM OUT =
f CO _ CV =
GMV × R CV × GM OUT
2 π C OUT
CCV Loop Definitions
Compensation of the CCV loop depends on the para-
meters and components shown in Figure 5. C CV and
R CV are the CCV loop compensation capacitor and
series resistor. R ESR is the equivalent series resistance
(ESR) of the charger output capacitor (C OUT ). R L is the
equivalent charger output load, where R L = V BATT /
I CHG . The equivalent output impedance of the GMV
amplifier, R OGMV ≥ 10M ? . The voltage amplifier
transconductance, GMV = 0.125μA/mV. The DC-DC
converter transconductance, GM OUT = 3.33A/V:
1
A CSI × RS 2
where A CSI = 20, and RS2 is the charging current-
sense resistor in the Typical Application Circuits.
The compensation pole is given by:
To calculate R CV and C CV values of the circuit of Figure 2:
Cells = 4
C OUT = 22μF
V BATT = 16.8V
I CHG = 2.5A
GMV = 0.125μA/mV
GM OUT = 3.33A/V
R OGMV = 10M ?
f = 400kHz
Choose crossover frequency to be 1/5th the
MAX1908’s 400kHz switching frequency:
= 80 kHz
Solving yields R CV = 26k ? .
Conservatively set R CV = 1k ? , which sets the crossover
f P _ CV =
1
2 π R OGMV × C CV
frequency at:
f CO_CV = 3kHz
Choose the output-capacitor ESR so the output-capacitor
The compensation zero is given by:
zero is 10 times the crossover frequency:
f Z _ CV =
1
2 π R CV × C CV
R ESR =
1
2 π × 10 × f CO _ CV × C OUT
= 0 . 24 ?
f P _ OUT =
The output pole is given by:
1
2 π R L × C OUT
22
f Z _ ESR =
1
2 π R ESR × C OUT
= 2 . 412 MHz
Maxim Integrated
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