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| 型号： | MCP1631RD-MCC1 |
| 厂商： | Microchip Technology |
| 文件页数： | 51/54页 |
| 文件大小： | 0K |
| 描述： | REFERENCE DESIGN FOR MCP1631HV |
| 标准包装： | 1 |
| 主要目的： | 电源管理，电池充电器 |
| 嵌入式： | 是，MCU，8 位 |
| 已用 IC / 零件： | MCP1631HV，PIC16F883 |
| 主要属性： | 1 ~ 2 芯锂离子电池，1 ~ 4 芯镍镉/镍氢电池 |
| 次要属性： | 状态 LED |
| 已供物品： | 板，CD |
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MCP1631HV MULTI-CHEMISTRY
BATTERY CHARGER
REFERENCE DESIGN
Appendix D. Design Example
D.1
DESIGN EXAMPLE
D.1.1
Design Parameters:
?
?
?
?
?
?
?
?
?
?
P OUT = 10W (typical)
V IN = 6V to 16V for MCP1631HV. Choose V IN = 6V for worst case (WC).
V OUT = 8.4V for two Li-Ion batteries or 6.6V for four NiMH batteries
I OUT = 1.5A for 4 NiMH batteries. Choose DI L = 20%, I OUT = 300 mA.
η = Switcher Efficiency @ 80% (typical)
V F = Schottky Diode Drop @ 0.35V (typical)
I IN_WC = I OUT * V OUT_WC /(V IN_WC * ?) = 1.5A * 6.6V/(6V * 0.8) = 2.06A
F OSC = 500 kHz, T SWITCH = 1/F SWITCH = 2 μs
D OSC = 25%, t OSC_ON = 0.5 μs, t OSC_OFF = 1.5 μs
Choose C20 (Artificial Ramp) = 1500 pF
D.1.2
Design:
? Duty Cycle (D) = ((V OUT + V F )/ η )/(((V OUT + V F )/ η ) + VIN )
= ((8.4V + 0.35)/0.8)/(((8.4V + 0.35)/0.8) + 6V)
= 65% (worst case is two Li-Ion batteries)
? t ON = D * 1/F SWITCH = 0.65/500 kHz = 1.3 μs
? t OFF = T SWITCH - t ON = 2 μs – 1.3 μs = 0.7 μs
? L = V IN * D * T SWITCH / Δ I L = 6V * 0.65 * 2 μs/300 mA = 26 μH.
For SEPIC coupled inductor, use ? L because V IN “sees” 2 inductors.
L COUPLED = 26 μH/2 = 13 μH. Choose 10 μH as standard value.
? Δ I L = 2 * V IN * D * T SWITCH / (4 * L COUPLED ) = 2*6V*0.65*2 μs/(4*10 μH)
Δ I L ? 390 mA
? Δ I IN = Δ I L = 390 mA
? I IN = I OUT * V OUT /(V IN * η )= 1.5A * 6.6V/( 6V * 0.8) = 2.06A
I IN PEAK = I IN + ? Δ I L = 2.06A + 0.195A = 2.26A
? P OUT = V OUT * I OUT = 6.6V * 1.5A = 9.9W
D.1.3
Slope Compensation:
? M Artificial Ramp = Δ I L * R SENSE /t OSC_FF
= 390 mA * 0.11 Ω /1.5 us = 0.0429V/1.5 μs
But the ramp divider is (R10 + R11)/(R10 + R11 + R35)
= (1k + 1k)/(1k + 1k + 20k) = 2k/22k = 1/11
= (0.0429V/1.5 μs)/(1/11) = 471.9 mV/1.5 μs
? τ Artificial Ramp (R33 & C20) - Using V OUT = V IN (1-e -(T/ τ ) )
= -t OFF /(Ln(1-(V OUT /V IN) ))
= -1.5 μs/(Ln(1 – (0.4719V/5.0V)))
= -1.5 μs/Ln (0.90562) = 15.13 μs
? 2009 Microchip Technology Inc.
DS51791A-page 47
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