
Notes:
Note 1. V
AGC
(P5 EXT. Applying Voltage) = 11.5V, PIF IN: f = 58.75MHz 1kHz 30% AM Modulation.
Adjust PIF input level (v
i
) so that the detected output of P
15A
with high impedance probe will
be 0.8V
P
–
P
and measure the input level.
Note 2. V
AGC
= 4V. Measure PIF input level (v
i
) same as Note 1.
Note 3. PIF IN: f = 58.75MHz CW 15mV
rms
. Measure DC level of P
15
.
Note 4. PIF IN: f = 58.75MHz, APL 100%, 87.5% AM modulation. P
5
: Ppen.
(1) Adjust PIF input level 50mV
P
–
P
and measure the detected output level v
01P
–
P
.
(2) Then increase the input level so that the detected output level will be 1.1 x v
01P
–
P
and measure the input level.
Note 5. V
AGC
= 8V. PIF IN: 58.75MHz
±
10MHz variable or sweep 15mV
rms
measure DC level of
P
15
.
Note 6. V
AGC
= 8V (GR = 30dB). SG
1
: 58.75MHz CW, SG
2
: 58.65 to 40MHz variable.
(1) Setting output of SG
1
so that DC level of P
15
will be 4V.
(2) Setting output of SG
2
(58.65MHz) so that AC level of P
15
will be 0.5V
P
–
P
.
(3) Decreaseing frequency of SG
2
until AC level of P
15
will be 0.35V
P
–
P
(
–
3dB of 0.5V
P
–
P
) then read f
SG2
= F, f
BW
= 58.75
–
F MHz
Note 7. SG
1:
58.75MHz, 1kHz 80% AM modulation 100mV
rms
. SG
2
, SG
3
: OFF. Setting V
AGC
so
that output AC level of P
15
will be 2.7V
P
–
P
. Measure CL of P
15
after setting to 0% AM of SG
1
.
Note 8. Measure I
2nd
of P
15
same as Note 7.
Note 9. V
AGC
= 8V. SG
1
: 58.75MHz (P = Picture) 100mV
rms
. SG
2
: 54.25MHz (S = Sound)
32mV
rms
(
–
10dB of SG
1
). SG
3
: 55.17MHz (C = Chroma) 32mV
rms
(
–
10dB of SG
1
).
(1) Seting V
AGC
so that the output tip level (lower) of P
15
will be 3V DC.
(2) Measure the level difference (dB) between c
–
level and 920kHz level.
Note10. V
AGC
= 8V. PIF IN: f = 58.75MHz video signal (ramp) 87,5% AM 100mV
P
–
P
. Setting ATT
so that the sync tip level of P
15
will be 2.5V DC. Measure DP and DG.
Note11. V
AGC
= 5V, f = 58.75MHz. Measure R
IN
, C
IN
.
Note12. AFT sensitivity
F/
(V
13
–
V
14
)
(1) INT, AGC (P
5
Open)
(2) PIF Input: 58.75MHz
±
1MHz, CW 15mV
rms
.
(3) Read the frequency (f
1
) of PIF when V
13
–
V
14
=
–
1V.
(4) Read the frequency (f
2
) of PIF when V
13
–
V
14
= 1V.
Then calculate
F/
(V
13
–
V
14
) = |f
1
–
f
2
|
Note13.
F
W
, V
13U
, V
14U
, V
13L
, V
14L
(1) INT AGC (P
5
Open)
(2) PIF IN: 58.75MHz
±
10MHz CW 15mV
rms
(3) 9pF at Pin16 should b shorted
(4) Read the frequency (f
1
or f
2
) when the V
5
or V
6
reduced to 90% level of A or B with
varing the frequency. Then band width is the difference from center requency (f
0
).
Note14. P
5
: Open. PIF IN: 58.75MHz CW 20mV
rms
.
(1) Adjust the voltage of Pin3 so that the voltage of Pin4 will be 6V DC.
(2) Measure the volatge at Pin3.
Note15. P
5
: Open. PIF IN: 58.75MHz, 100% APL 87.5% AM modulation signal amplitude 50mV
P
–
P
.
Measure detected output voltge (White peak to sync tip).
Note16. P
5
: Open. SG
1
: 58.75MHz CW 100mV
rms
. SG
2
: 54.25MHz CW 25mV
rms
. Measure SIF
(4.5MHz) output voltage at P
15
.
Note17. SIF IN: f = 4.5MHz, FM f
MOD
= 400Hz,
f =
±
25kHz.
(1) Adjust SIF input level 100mV
P
–
P
and measure the detected output level v
OS
.
(2) Then decrease the input level so that the detected output level will be 3dB down of
v
OS
and measure the input level.