参数资料
型号: NUF4211MNT1G
厂商: ON Semiconductor
文件页数: 4/6页
文件大小: 0K
描述: IC EMI FILTER 4LINE ESD 8-DFN
标准包装: 3,000
类型: 低通
技术: RC(Pi)
通道数: 4
中心 / 截止频率: 250MHz(截止值)
衰减值: 20dB @ 800MHz ~ 3GHz
电阻 - 通道 (Ohms): 100
值: R = 100 欧姆,C = 8.5pF
ESD 保护:
滤波器阶数: 2nd
应用: 移动设备的数据线路
封装/外壳: 8-VFDFN 裸露焊盘
尺寸/尺寸: 0.079" L x 0.079" W(2.00mm x 2.00mm)
高度: 0.039"(1.00mm)
包装: 带卷 (TR)
工作温度: -40°C ~ 85°C
NUF4211MN
Theory of Operation
The NUF4211MN combines ESD protection and EMI
filtering conveniently into a small package for today’s size
constrained applications. The capacitance inherent to a
typical protection diode is utilized to provide the
capacitance value necessary to create the desired frequency
response based upon the series resistance in the filter. By
combining this functionality into one device, a large number
of discrete components are integrated into one small
package saving valuable board space and reducing BOM
count and cost in the application.
Application Example
The accepted practice for specifying bandwidth in a filter
is to use the 3 dB cutoff frequency. Utilizing points such as
the 6 dB or 9 dB cutoff frequencies results in signal
degradation in an application. This can be illustrated in an
application example. A typical application would include
EMI filtering of data lines in a camera or display interface.
approximation of a square wave, shown below in Equations
1 and 2 in the Fourier series approximation.
From this it can be seen that a square wave consists of odd
order harmonics and to fully construct a square wave n must
go to infinity. However, to retain an acceptable portion of the
waveform, the first two terms are generally sufficient. These
two terms contain about 85% of the signal amplitude and
allow a reasonable square wave to be reconstructed.
Therefore, to reasonably pass a square wave of frequency x
the minimum filter bandwidth necessary is 3x . All ON
Semiconductor EMI filters are rated according to this
principle. Attempting to violate this principle will result in
significant rounding of the waveform and cause problems in
transmitting the correct data. For example, take the filter
with the response shown in Figure 7 and apply three
different data waveforms. To calculate these three different
frequencies, the 3 dB, 6 dB, and 9 dB bandwidths will be
used.
S
In such an example it is important to first understand the
signal and its spectral content. By understanding these
things, an appropriate filter can be selected for the desired
application. A typical data signal is pattern of 1’s and 0’s
transmitted over a line in a form similar to a square wave.
Equation 1:
2 2
x(t) + 1 ) p
a
1
n + 1 2n * 1
sin((2n * 1) w 0 t)
(eq. 1)
The maximum frequency of such a signal would be the
Equation 2 (simplified form of Equation 1):
pattern 1-0-1-0 such that for a signal with a data rate of
100 Mbps, the maximum frequency component would be
50 MHz. The next item to consider is the spectral content of
2 2
x(t) + 1 ) p
sin( w 0 t)
1
)
sin(3 w 0 t)
3
)
sin(5 w 0 t)
5
) AAA (eq. 2)
the signal, which can be understood with the Fourier series
? 3 dB
? 6 dB
? 9 dB
f 1
f 2
f 3
100k
1M
10M
100M
1G
10G
Frequency (Hz)
Figure 7. Filter Bandwidth
From the above paragraphs it is shown that the maximum
Table 2. Frequency Chart
supported frequency of a waveform that can be passed
through the filter can be found by dividing the bandwidth by
a factor of three (to obtain the corresponding data rate
multiply the result by two). The following table gives the
bandwidth values and the corresponding maximum
supported frequencies and the third harmonic frequencies.
Bandwidth
3 dB–100 MHz
6 dB–200 MHz
9 dB–300 MHz
Maximum Supported
Frequency
33.33 MHz (f 1 )
66.67 MHz (f 2 )
100 MHz (f 3 )
Third Harmonic
Frequency
100 MHz
200 MHz
300 MHz
http://onsemi.com
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