参数资料
型号: PKL4311PIPTSP
厂商: ERICSSON POWER MODULES AB
元件分类: 电源模块
英文描述: 1-OUTPUT 300 W DC-DC REG PWR SUPPLY MODULE
文件页数: 35/42页
文件大小: 828K
代理商: PKL4311PIPTSP
40
EN/LZT 146 047 R4A Ericsson Power Modules, June 2004
PKL 4000 Series Datasheet
0123
0
1
2
3
4
5
6
[m/s]
[°C/W]
Thermal Consideration
General
The PKL 4000 Series DC/DC converters are designed to
operate in a variety of thermal environments, however
sufficient cooling should be provided to help ensure reliable
operation. Heat is removed by conduction, convection and
radiation to the surrounding environment. Increased airflow
enhances the heat transfer via convection. The available load
current vs. ambient air temperature and airflow at Vin=53 V
for each model is according to the information given under
the output section. The test is done in a wind tunnel with a
cross section of 305x305 mm, the DC/DC converter vertically
mounted on a 16 layer PCB with a size of 254x254 mm.
Proper cooling can be verified by measuring the temperature
of selected devices.
Calculation of ambient temperature
By using the thermal resistance the maximum allowed
ambient temperature can be calculated.
1. The powerloss is calculated by using the formula
((1/
η) - 1) × output power = power losses.
η = efciency of converter. E.g 85 % = 0.85
2. Find the value of the thermal resistance in the diagram
by using the airow speed at the module. Take the thermal
resistance x powerloss to get the temperature increase.
Thermal resistance vs. airspeed measured at the converter.
Tested in windtunnel with a cross section of 305×305 mm
mounted on a 16 layer PCB with a size of 254×254 mm.
3. Max allowed calculated ambient temperature is: Max
TC of DC/DC converter –temperature increase.
Example: PKL 4118B PIT
Conditions:
Input voltage 53 V
Max case temperature 110 °C
Output current 80 A
Efciency 81.5%
Airow 2 m/s
2. 32.6W × 1.8 °C/W = 58.68 °C (temperature increase)
3. 110 °C - 58.7 °C = max ambient temperature is 51.3 °C
The real temperature will be dependent on several factors,
like PCB size and type, direction of airow, air turbulence,
heatsinking etc. It is recommended to verify the temperature
by testing.
1. ((
) - 1) × 144 W = 32.6 W (powerloss)
1
0.815
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