参数资料
型号: SC4524CSETRT
厂商: Semtech
文件页数: 15/22页
文件大小: 0K
描述: IC REG BUCK ADJ 2A 8SOIC
标准包装: 1
类型: 降压(降压)
输出类型: 可调式
输出数: 1
输出电压: 1 V ~ 26.88 V
输入电压: 3 V ~ 28 V
PWM 型: 电流模式
频率 - 开关: 300kHz ~ 1.3MHz
电流 - 输出: 2A
同步整流器:
工作温度: -40°C ~ 105°C
安装类型: 表面贴装
封装/外壳: 8-SOIC(0.154",3.90mm Width)裸露焊盘
包装: 标准包装
供应商设备封装: 8-SOIC-EP
其它名称: SC4524CSEDKR
SC4524C
Applications Information (Cont.)
Therefore, the procedure of the voltage loop design for
the SC4524C can be summarized as:
Then the compensator parameters are
10 20
0.3 x 10 ? 3
= 0.8 nF
2 π x 16 x 10 x 12.4 x 10 3
= 21 pF
( )Plottheconvertergain,i.e.controltofeedbacktransfer
function.
(2) Select the open loop crossover frequency, F C , between
 0% and 20% of the switching frequency. At F C , find the
required compensator gain, A C . In typical applications with
ceramic output capacitors, the ESR zero is neglected and
the required compensator gain at F C can be estimated by
R 7 =
C 5 =
C 8 =
11.4
= 12.4 k
1
3
1
2 π x 600 x 10 3 x 12.4 x 10 3
A C = ? 20 x log ? ?
1 1
V FB ?
V O ? ?
?
?
x
G CA R S 2 π F C C O
x
?
Select R 7 = 2.4k, C 5 = nF, and C 8 =22pF for the design.
Compensator parameters for various typical applications
are listed in Table 5. A MathCAD program is also available
(3) Place the compensator zero, F Z  , between  0% and
20% of the crossover frequency, F C .
(4) Use the compensator pole, F P  , to cancel the ESR zero, F Z .
(5) Then, the parameters of the compensation network
can be calculated by
upon request for detailed calculation of the compensator
parameters.
Thermal Considerations
For the power transistor inside the SC4524C, the
10 20
P SW =
x t S x V IN x I O x F SW
= D x V BST x O
P BST
R 7 =
C 5 =
C 8 =
A C
g m
1
2 π F Z 1 R 7
1
2 π F P 1 R 7
conduction loss P C , the switching loss P SW , and bootstrap
circuit loss P BST, can be estimated as follows:
P C = D x V CESAT x I O
1
2
I
40
where g m =0.3mA/V is the EA gain of the SC4524C.
where V BST is the BST supply voltage and t S is the equivalent
switching time of the NPN transistor (see Table 4).
Example : Determine the voltage compensator for an
800kHz,  2V to 3.3V/2A converter with 22uF ceramic
output capacitor.
Choose a loop gain crossover frequency of 80kHz, and
Input Voltage
12V
24V
28V
Load Current
1A 2A
12.5ns 15.3ns
22ns 25ns
25.3ns 28ns
place voltage compensator zero and pole at F Z  = 6kHz
(20% of F C ), and F P  =600kHz. From the equation in step
(2), the required compensator gain at F C is
Table 4. Typical switching time
In addition, the quiescent current loss is
 
P Q  = V IN  x 2mA
 5
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