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参数资料
| 型号： | TC2576VAT |
| 元件分类： | 稳压器 |
| 英文描述： | 7.5 A SWITCHING REGULATOR, 63 kHz SWITCHING FREQ-MAX, PSFM5 |
| 封装： | TO-220, 5 PIN |
| 文件页数： | 25/25页 |
| 文件大小： | 213K |
| 代理商： | TC2576VAT |
9
TC2576
TC2576-2 12/04/00
3.0A Step-Down Switching Regulator
2001 Microchip Technology Inc.
DS21399A
Procedure (Adjustable Output Version: TC2576-ADJ) (Continued)
Procedure
Example
3. Catch Diode Selection (D1)
A. Since the diode maximum peak current exceeds the
regulator maximum load current the catch diode current
rating must be at least 1.2 times greater than the
maximum load current. For a robust design, the diode
should have a current rating equal to the maximum
current limit of the TC2576 to be able to with stand a
continuous output short.
B. The reverse voltage rating of the diode should be at least
1.25 times the maximum input voltage.
4. Inductor Selection (L1)
A. Use the following formula to calculate the inductor
Volt x microsecond [V x
s] constant:
E x T = ( VIN – VOUT)
VOUT
x
10
6
[V x
sec]
VIN
F[Hz]
B. Match the calculated E x T value with the corresponding
number on the vertical axis of the Inductor Value
Selection Guide shown in Figure 37. This E x T constant
is a measure of the energy handling capability of an
inductor and is dependent upon the type of core, the core
area, the number of turns, and the duty cycle.
C. Next step is to identify the inductance region intersected
by the E x T value and the maximum load current value
on the horizontal axis shown in Figure 7.
D. From the inductor code, identify the inductor value. Then
select an appropriate inductor from Table 2. The inductor
chosen must be rated for a switching frequency of 52kHz
and for a current rating of 1.15 x ILOAD . The inductor
current rating can also be determined by calculating the
inductor peak current:
IP (max) = ILOAD(max) +
(VIN – VOUT) tON
2L
where tON is the "on" time of the power switch and
tON =
(VOUT
x
1.0 )
VIN
fOSC
For additional information about the inductor, see
the inductor section in the “External Components”
section of this data sheet.
3. Catch Diode Selection (D1)
A. For this example, a 3.0A current rating is adequate.
B. Use a 30V IN5821 Schottky diode or any suggested
fast recovery diodes in Table 1.
4. Inductor Selection (L1)
A. Calculate E x T [V x
sec] constant:
E x T = ( 25 – 8.0) x
8.0
x
1000
= 80 [V x
sec]
25
52
B. E x T = 80 [V x
sec]
C. ILOAD(max) = 2.5 A
Inductance Region = H150
D. Proper inductor value = 150
H
Choose the inductor from Table 2.
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