参数资料
型号: TPS40051PWPR
厂商: TEXAS INSTRUMENTS INC
元件分类: 稳压器
英文描述: 0.2 A SWITCHING CONTROLLER, 1000 kHz SWITCHING FREQ-MAX, PDSO16
封装: GREEN, PLASTIC, HTSSOP-16
文件页数: 4/36页
文件大小: 648K
代理商: TPS40051PWPR
TPS40050
TPS40051
TPS40053
SLUS540F DECEMBER 2002 REVISED JUNE 2004
www.ti.com
12
APPLICATION INFORMATION
SELECTING THE INDUCTOR VALUE
The inductor value determines the magnitude of ripple current in the output capacitors as well as the load current
at which the converter enters discontinuous mode. Too large an inductance results in lower ripple current but
is physically larger for the same load current. Too small an inductance results in larger ripple currents and a
greater number of (or more expensive output capacitors for) the same output ripple voltage requirement. A good
compromise is to select the inductance value such that the converter doesn’t enter discontinuous mode until
the load approximated somewhere between 10% and 30% of the rated output. The inductance value is
described in equation (6).
L
+
V
IN * VO
V
O
V
IN
DI
f
SW
(Henries)
where:.
D VO is the output voltage
D I is the peak-to-peak inductor current
CALCULATING THE OUTPUT CAPACITANCE
The output capacitance depends on the output ripple voltage requirement, output ripple current, as well as any
output voltage deviation requirement during a load transient.
The output ripple voltage is a function of both the output capacitance and capacitor ESR. The worst case output
ripple is described in equation (7).
DV + DI ESR )
1
8
C
O
f
SW
V
P
*P
The output ripple voltage is typically between 90% and 95% due to the ESR component.
The output capacitance requirement typically increases in the presence of a load transient requirement. During
a step load, the output capacitance must provide energy to the load (light to heavy load step) or absorb excess
inductor energy (heavy to light load step) while maintaining the output voltage within acceptable limits. The
amount of capacitance depends on the magnitude of the load step, the speed of the loop and the size of the
inductor.
Stepping the load from a heavy load to a light load results in an output overshoot. Excess energy stored in the
inductor must be absorbed by the output capacitance. The energy stored in the inductor is described in
equation (8).
E
L +
1
2
L
I2 (Joules)
where:
I2
+ I
OH
2
* I
OL
2
(Amperes)
2
where:
D IOH is the output current under heavy load conditions
D IOL is the output current under light load conditions
(6)
(7)
(8)
(9)
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