参数资料
型号: TPS61097-18DBVT
厂商: TEXAS INSTRUMENTS INC
元件分类: 稳压器
英文描述: 0.475 A BATTERY CHARGE CONTROLLER, PDSO5
封装: 2.80 X 2.90 MM, PLASTIC, SOT-23, 5 PIN
文件页数: 11/26页
文件大小: 0K
代理商: TPS61097-18DBVT
TPS61097-33
V
0.9 V to 3.3V
IN
VOUT
EN
L
GND
VIN
L1
R2
R1
C1
C2
V
+3.3V
OUT
IN
OUT
IN
OUT
V
(V
- V )
1
L =
f 200 mA
V
ì
í
OUT
IN
L,MAX
V
I
+ 100 mA;
continous current operation
0.8 V
I
=
200 mA;
discontinuous current operation
>
OUT
IN
V
I
0.8
100 mA
V
TPS61097
www.ti.com
SLVS872B – JUNE 2009 – REVISED DECEMBER 2009
Figure 19. Adjustable Bypass Switching
Inductor Selection
To make sure that the TPS61097 devices can operate, a suitable inductor must be connected between pin VIN
and pin L. Inductor values of 4.7
μH show good performance over the whole input and output voltage range .
Choosing other inductance values affects the switching frequency f proportional to 1/L as shown in Equation 2.
(2)
Choosing inductor values higher than 4.7
μH can improve efficiency due to reduced switching frequency and
therefore with reduced switching losses. Using inductor values below 2.2
μH is not recommended.
Having selected an inductance value, the peak current for the inductor in steady state operation can be
calculated. Equation 3 gives the peak current estimate.
(3)
IL,MAX is the inductor's required minimum current rating. Note that load transient or over current conditions may
require an even higher current rating.
Equation 4 provides an easy way to estimate whether the device is operating in continuous or discontinuous
operation. As long as the equation is true, continuous operation is typically established. If the equation becomes
false, discontinuous operation is typically established.
(4)
Due to the use of current hysteretic control in the TPS61097, the series resistance of the inductor can impact the
operation of the main switch. There is a simple calculation that can ensure proper operation of the TPS61097
boost converter. The relationship between the series resistance (RIN), the input voltage (VIN) and the switch
current limit (ISW) is shown in Equation 5.
RIN < VIN / ISW
(5)
Examples:
ISW = 400 mA, VIN = 2.5 V
(6)
In Equation 6, RIN < 2.5 V / 400 mA; therefore, RIN must be less than 6.25 .
Copyright 2009, Texas Instruments Incorporated
19
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