参数资料
型号: TS4984EIKJT
厂商: STMICROELECTRONICS
元件分类: 音频/视频放大
英文描述: 1.2 W, 2 CHANNEL, AUDIO AMPLIFIER, PBGA15
封装: LEAD FREE, FCP-15
文件页数: 14/30页
文件大小: 1644K
代理商: TS4984EIKJT
TS4984FC
Application Information
21/30
and the maximum value is obtained when:
and its value is:
Note:
This maximum value is only depending on power supply voltage and load values.
The efficiency,
η, is the ratio between the output power and the power supply:
The maximum theoretical value is reached when
VPEAK = VCC, so that:
The TS4984 has two independent power amplifiers, and each amplifier produces heat due to its
power dissipation. Therefore, the maximum die temperature is the sum of the each amplifier’s
maximum power dissipation. It is calculated as follows:
Pdiss1 = Power dissipation due to the 1st channel power amplifier.
Pdiss2 = Power dissipation due to the 2nd channel power amplifier.
Total Pdiss =Pdiss1 +Pdiss2 (W)
In most cases, Pdiss1 = Pdiss2, giving:
or, stated differently:
4.5
Decoupling the circuit
Two capacitors are needed to correctly bypass the TS4984. A power supply bypass capacitor
CS and a bias voltage bypass capacitor Cb.
CS has particular influence on the THD+N in the high frequency region (above 7kHz) and an
indirect influence on power supply disturbances. With a value for CS of 1F, you can expect
similar THD+N performances to those shown in the datasheet. For example:
In the high frequency region, if CS is lower than 1F, it increases THD+N and disturbances
on the power supply rail are less filtered.
On the other hand, if CS is higher than 1F, those disturbances on the power supply rail
are more filtered.
Cb has an influence on THD+N at lower frequencies, but its function is critical to the final result
of PSRR (with input grounded and in the lower frequency region), in the following manner:
If Cb is lower than 1F, THD+N increases at lower frequencies and PSRR worsens.
P
diss
P
ou t
------------------ = 0
P
dissmax
2V
cc
2
π2R
L
-------------
=
W
()
η =
P
ou t
P
su pp ly
------------------- =
πV
PEAK
4V
CC
-----------------------
π
4
----- = 78.5%
Total P
diss
P
d iss1
P
diss2
(W)
=
Total P
diss
42V
CC
π R
L
---------------------- P
out
2P
out
=
W
()
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