参数资料
型号: ISL62883HRTZ-T
厂商: Intersil
文件页数: 15/37页
文件大小: 0K
描述: IC REG PWM 3PHASE BUCK 40TQFN
标准包装: 6,000
应用: 控制器,Intel IMVP-6.5?
输入电压: 5 V ~ 21 V
输出数: 1
输出电压: 0.013 V ~ 1.5 V
工作温度: -10°C ~ 100°C
安装类型: 表面贴装
封装/外壳: 40-WFQFN 裸露焊盘
供应商设备封装: 40-TQFN-EP(5x5)
包装: 带卷 (TR)
ISL62883, ISL62883B
VCC SENSE + V = V DAC + VSS SENSE
Differential Sensing
Figure 9 also shows the differential voltage sensing scheme.
VCC SENSE and VSS SENSE are the remote voltage sensing signals
from the processor die. A unity gain differential amplifier senses the
VSS SENSE voltage and add it to the DAC output. The error amplifier
regulates the inverting and the non-inverting input voltages to be
equal as shown in Equation 3:
(EQ. 3)
droop
The ISL62883 will adjust the phase pulse-width relative to the
other phases to make V ISEN1 = V ISEN2 = V ISEN3 , thus to achieve
I L1 = I L2 = I L3 , when there are R dcr1 = R dcr2 = R dcr3 and
R pcb1 = R pcb2 = R pcb3 .
Using same components for L1, L2 and L3 will provide a good
match of R dcr1 , R dcr2 and R dcr3 . Board layout will determine
R pcb1 , R pcb2 and R pcb3 . It is recommended to have symmetrical
layout for the power delivery path between each inductor and the
output voltage rail, such that R pcb1 = R pcb2 = R pcb3 .
Rpcb3
V3n
V2n
Rpcb1
V1n
Rewriting Equation 3 and substitution of Equation 2 gives:
VCC SENSE – VSS SENSE = V DAC – R droop × I droop (EQ. 4)
Equation 4 is the exact equation required for load line
implementation.
The VCC SENSE and VSS SENSE signals come from the processor
die. The feedback will be open circuit in the absence of the
processor. As shown in Figure 9, it is recommended to add a
“catch” resistor to feed the VR local output voltage back to the
compensator, and add another “catch” resistor to connect the VR
local output ground to the RTN pin. These resistors, typically
10 Ω ~100 Ω , will provide voltage feedback if the system is
powered up without a processor installed.
ISEN3
INTERNAL
TO IC
ISEN2
ISEN1
V3p
Phase3
Rs
Rs
Cs
Rs
V2p
Phase2
Rs
Rs
Cs
Rs
V1p
Phase1
Rs
Rs
Cs
L3
L2
L1
Rdcr3
IL3
Rdcr2 Rpcb2
IL2
Rdcr1
IL1
Vo
Phase Current Balancing
Rs
ISEN3
Phase3
Rs
L3
IL3
Rdcr3
Rpcb3
FIGURE 11. DIFFERENTIAL-SENSING CURRENT BALANCING
CIRCUIT
INTERNAL
TO IC
ISEN2
ISEN1
Cs
Phase2
Rs
Cs
Phase1
Rs
Cs
L2
L1
IL2
IL1
Rdcr2
Rdcr1
Rpcb2
Rpcb1
Vo
Sometimes, it is difficult to implement symmetrical layout. For
the circuit shown in Figure 10, asymmetric layout causes
different R pcb1 , R pcb2 and R pcb3 thus current imbalance.
Figure 11 shows a differential-sensing current balancing circuit
recommended for ISL62883. The current sensing traces should
be routed to the inductor pads so they only pick up the inductor
DCR voltage. Each ISEN pin sees the average voltage of three
sources: its own phase inductor phase-node pad, and the other
two phases inductor output side pads. Equations 8 thru 10 give
FIGURE 10. CURRENT BALANCING CIRCUIT
The ISL62883 monitors individual phase average current by
monitoring the ISEN1, ISEN2, and ISEN3 voltages. Figure 10
shows the current balancing circuit recommended for ISL62883.
Each phase node voltage is averaged by a low-pass filter
the ISEN pin voltages:
V ISEN1 = V 1p + V 2n + V 3n
V ISEN2 = V 1n + V 2p + V 3n
V ISEN3 = V 1n + V 2n + V 3p
(EQ. 8)
(EQ. 9)
(EQ. 10)
consisting of R s and C s , and presented to the corresponding ISEN
pin. R s should be routed to inductor phase-node pad in order to
eliminate the effect of phase node parasitic PCB DCR.
The ISL62883 will make V ISEN1 = V ISEN2 = V ISEN3 as in:
V 1p + V 2n + V 3n = V 1n + V 2p + V 3n (EQ. 11)
Equations 5 thru 7 give the ISEN pin voltages:
V 1n + V 2p + V 3n = V 1n + V 2n + V 3p
(EQ. 12)
V ISEN1 = ( R dcr1 + R pcb1 ) × I L1
(EQ. 5)
Rewriting Equation 11 gives:
V ISEN2 = ( R dcr2 + R pcb2 ) × I L2
V ISEN3 = ( R dcr3 + R pcb3 ) × I L3
(EQ. 6)
(EQ. 7)
V 1p – V 1n = V 2p – V 2n
and rewriting Equation 12 gives:
V 2p – V 2n = V 3p – V 3n
(EQ. 13)
(EQ. 14)
where R dcr1 , R dcr2 and R dcr3 are inductor DCR; R pcb1 , R pcb2
and R pcb3 are parasitic PCB DCR between the inductor output
side pad and the output voltage rail; and I L1 , I L2 and I L3 are
inductor average currents.
15
Combining Equations 13 and 14 gives :
V 1p – V 1n = V 2p – V 2n = V 3p – V 3n
Therefore:
R dcr1 × I L1 = R dcr2 × I L2 = R dcr3 × I L3
(EQ. 15)
(EQ. 16)
FN6891.4
June 21, 2011
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