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Liteon Semiconductor Corporation
LSP3171
MSOP10L 2A Step Down DC/DC Converter
Rev1.4
5/9
For ceramic output capacitors, typically choose a capacitance of about 22F. For tantalum or electrolytic capacitors,
choose a capacitor with less than 50m ESR.
Rectifier Diode
Use a Schottky diode as the rectifier to conduct current when the High-Side Power Switch is off. The Schottky diode
must have a current rating higher than the maximum output current and a reverse voltage rating higher than the
maximum input voltage.
Stability Compensation
CCOMP2 is needed only for high ESR output capacitor
Figure 2. Stability Compensation
The feedback loop of the IC is stabilized by the components at the COMP pin, as shown in Figure 2. The DC loop
gain of the system is determined by the following equation:
(4)
The dominant pole P1 is due to CCOMP:
COMP
VEA
EA
1
P
C
A
π
2
G
f
=
(5)
The second pole P2 is the output pole:
OUT
2
P
C
V
π
2
I
f
=
(6)
The first zero Z1 is due to RCOMP and CCOMP:
COMP
1
Z
C
R
π
2
1
f
=
(7)
And finally, the third pole is due to RCOMP and CCOMP2 (if CCOMP2 is used):
2
COMP
3
P
C
R
π
2
1
f
=
(8)
The following steps should be used to compensate the IC:
STEP1. Set the crossover frequency at 1/10 of the switching frequency via RCOMP:
(9)
but limit RCOMP to 3.4k maximum.
STEP2. Set the zero fZ1 at 1/4 of the crossover frequency. If RCOMP is less than 3.4k, the equation for CCOMP
is:
)
F
(
R
10
8
.
1
C
COMP
5
COMP
×
=
(10)
If RCOMP is limited to 3.4k, then the actual crossover frequency is 3.4 / (VOUTCOUT). Therefore:
)
F
(
C
V
10
2
.
1
C
OUT
5
COMP
×
=
(11)
STEP3. If the output capacitor’s ESR is high enough to cause a zero at lower than 4 times the crossover frequency,
an additional compensation capacitor CCOMP2 is required. The condition for using CCOMP2 is:
ESRCOUT
R
)
(
V
012
.
0
,
C
10
1
.
1
Min
OUT
6
×
≥
(12)