参数资料
型号: LT3083EFE#PBF
厂商: Linear Technology
文件页数: 17/28页
文件大小: 0K
描述: IC REG LDO ADJ 3A 16-TSSOP
标准包装: 95
稳压器拓扑结构: 正,可调式
输出电压: 可调至 23V
输入电压: 1.2 V ~ 23 V
电压 - 压降(标准): 1.25V @ 3A
稳压器数量: 1
电流 - 输出: 3A
电流 - 限制(最小): 3A
工作温度: -40°C ~ 125°C
安装类型: 表面贴装
封装/外壳: 16-TSSOP(0.173",4.40mm)裸露焊盘
供应商设备封装: 16-TSSOP-EP
包装: 管件
LT3083
APPLICATIONS INFORMATION
R P =
= 3.65 ?
The second technique for reducing power dissipation,
shown in Figure 8, uses a resistor in parallel with the
LT3083. This resistor provides a parallel path for current
flow, reducing the current flowing through the LT3083.
This technique works well if input voltage is reasonably
constant and output load current changes are small. This
technique also increases the maximum available output
current at the expense of minimum load requirements.
As an example, assume: V IN = V CONTROL = 5V, V IN(MAX) =
5.5V, V OUT = 3.3V, V OUT(MIN) = 3.2V, I OUT(MAX) = 2A and
I OUT(MIN) = 0.7A. Also, assuming that R P carries no more
than 90% of I OUT(MIN) = 630mA.
Calculating R P yields:
5.5V ? 3.2V
0.63A
(5% Standard Value = 3.6?)
C1
V CONTROL
LT3083
IN
V IN
The maximum total power dissipation is (5.5V – 3.2V) ?
2A = 4.6W. However, the LT3083 supplies only:
2A ?
= 1.36A
+
SET
R SET
3083 F08
OUT
R P
C2
V OUT
5.5V ? 3.2V
3.6 ?
Therefore, the LT3083’s power dissipation is only:
P DISS = (5.5V – 3.2V) ? 1.36A = 3.13W
Figure 8. Reducing Power Dissipation Using a Parallel Resistor
R P dissipates 1.47W of power. As with the first technique,
choose appropriate wattage resistors to handle and dis-
sipate the power properly. With this configuration, the
LT3083 supplies only 1.36A. Therefore, load current can
increase by 1.64A to a total output current of 3.64A while
keeping the LT3083 in its normal operating range.
3083fa
17
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