参数资料
型号: LT3433EFE#TRPBF
厂商: Linear Technology
文件页数: 12/16页
文件大小: 0K
描述: IC REG BUCK BST ADJ 0.5A 16TSSOP
标准包装: 2,500
类型: 降压(降压),升压(升压)
输出类型: 可调式
输出数: 1
输出电压: 3.3 V ~ 20 V
输入电压: 4 V ~ 60 V
PWM 型: 电流模式,混合
频率 - 开关: 200kHz
电流 - 输出: 500mA
同步整流器:
工作温度: -40°C ~ 125°C
安装类型: 表面贴装
封装/外壳: 16-TSSOP(0.173",4.40mm)裸露焊盘
包装: 带卷 (TR)
供应商设备封装: 16-TSSOP-EP
LT3433
APPLICATIO S I FOR ATIO
Design Example
CALCULATED VALUES
4V-60V to 5V DC/DC converter (the application on the
front page of this data sheet), load capability for T A = 85 ° C.
ITERATION #
1
SEED ? I
0
I SW
0.55
DC
0.683
? I
0.095
Application Specific
Constants:
LT3433 W/C Constants:
2
3
0.095
0.098
0.503
0.501
0.674
0.674
0.098
0.098
V IN = 4V
V OUT = 5V
L = 100 μ H
R L = 0.28 ?
V F1 = 0.45V
V F2 = 0.4V
R CESR = 0.01 ?
I MAX = 0.55A
R SWH = 1.2 ?
R SWL = 1 ?
f O = 190kHz
? BST = 0.05
? OUT = 0.05
I VIN = 600 μ A
I BIAS = 800 μ A
After iteration, DC = 0.674 and ? I = 0.098.
Use iteration result for DC and above design constants to
solve the I OUT(MAX) relation:
I OUT(MAX) = 0.501 ? [1 – 0.674 ? (1 + 0.05 + 0.05)] –
800 μ A
I OUT(MAX) = 129mA
Increased Output Voltages
The LT3433 operates in bridged mode with V IN = 4V, so the
relations used are:
DC = [V OUT + V F1 + V F2 – I SW ? (R L + R ESR )]/[V IN –
I SW ? (R SWH + R SWL + 2R L + R ESR ) + V OUT + V F1 +
V F2 ]
? I = (V OUT + V F1 + V F2 - I SW ? R L ) ? (1 – DC)/(L ? f O )
I OUT(MAX) = I SW ? [1 – DC ? (1 + ? BST + ? OUT )] – I BIAS
Iteration procedure for DC:
(1) Set initial seed value for ? I (this example will set
? I = 0).
(2) Using seed value for ? I, determine I SW (I SW = 0.55 –
0 = 0.55).
(3) Use calculated I SW and above design constants to
solve the DC relation (DC = 0.683).
The LT3433 can be used in converter applications with
output voltages from 3.3V through 20V, but as converter
output voltages increase, output current and duty cycle
limitations prevent operation with V IN at the extreme low
end of the LT3433 operational range. When a converter
operates as a buck/boost, the output current becomes
discontinuous, which reduces output current capability by
roughly a factor of 1 – DC, where DC = duty cycle. As such,
the output current requirement dictates a minimum input
voltage where output regulation can be maintained.
Typical Minimum Input Voltage as a Function of
Output Voltage and Required Load Current
24
20
200mA
(4) Use calculated DC to solve the ? I relation (yields ? I =
0.0949).
(5) If calculated ? I is equal to the seed value, stop.
Otherwise, use calculated ? I as new seed value and
repeat (2) through (4).
16
12
8
175mA
125mA
150mA
4
4
8
12
16
20
V OUT (V)
3433 AI03
3433f
12
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