参数资料
型号: LT6600IS8-10
厂商: Linear Technology
文件页数: 15/16页
文件大小: 0K
描述: IC AMP DIFF 10MHZ LP FLTR 8-SOIC
标准包装: 100
放大器类型: 差分
电路数: 1
输出类型: 差分
电流 - 输入偏压: 40µA
电压 - 输入偏移: 8000µV
电流 - 电源: 36mA
电压 - 电源,单路/双路(±): 3 V ~ 11 V,±1.5 V ~ 5.5 V
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 8-SOIC(0.154",3.90mm 宽)
供应商设备封装: 8-SO
包装: 管件
LT6600-10
8
66001fe
APPLICATIONS INFORMATION
Interfacing to the LT6600-10
Note: The referenced pin numbers correspond to the S8
package. See the Pin Functions section for the equivalent
DFN-12 package pin numbers.
The LT6600-10 requires 2 equal external resistors, RIN, to
set the differential gain to 402Ω/RIN. The inputs to the lter
are the voltages VIN+ and VIN– presented to these external
components, Figure 1. The difference between VIN+ and
VIN– is the differential input voltage. The average of VIN+
and VIN– is the common mode input voltage. Similarly,
the voltages VOUT+ and VOUT– appearing at Pins 4 and 5
of the LT6600-10 are the lter outputs. The difference
between VOUT+ and VOUT– is the differential output voltage.
The average of VOUT+ and VOUT– is the common mode
output voltage.
Figure 1 illustrates the LT6600-10 operating with a single
3.3V supply and unity passband gain; the input signal is
DC coupled. The common mode input voltage is 0.5V and
the differential input voltage is 2VP-P. The common mode
output voltage is 1.65V and the differential output voltage
is 2VP-P for frequencies below 10MHz. The common mode
output voltage is determined by the voltage at VOCM. Since
VOCM is shorted to VMID the output common mode is the
mid-supply voltage. In addition, the common mode input
voltage can be equal to the mid-supply voltage of VMID(refer
to the Distortion vs Input Common Mode Level graphs in
the Typical Performance Characteristics section).
Figure 2 shows how to AC couple signals into the
LT6600-10. In this instance, the input is a single-ended
signal. AC-coupling allows the processing of single-ended
or differential signals with arbitrary common mode levels.
The 0.1μF coupling capacitor and the 402Ω gain setting
resistor form a high pass lter, attenuating signals below
4kHz. Larger values of coupling capacitors will proportion-
ally reduce this highpass 3dB frequency.
In Figure 3 the LT6600-10 is providing 12dB of gain. The
gain resistor has an optional 62pF in parallel to improve
the passband atness near 10MHz. The common mode
output voltage is set to 2V.
Use Figure 4 to determine the interface between the
LT6600-10 and a current output DAC. The gain, or
“transimpedance”, is dened as A = VOUT/IINΩ.Tocompute
the transimpedance, use the following equation:
A
=
402 R1
R1
+R2
Ω
By setting R1 + R2 = 402Ω, the gain equation reduces
to A = R1Ω.
The voltage at the pins of the DAC is determined by R1,
R2, the voltage on VMID and the DAC output current (IIN+
or IIN–). Consider Figure 4 with R1 = 49.9Ω and R2 =
348Ω. The voltage at VMID is 1.65V. The voltage at the
DAC pins is given by:
V
DAC = VPIN7
R1
+R2+ 402
+I
IN
R1 R2
R1
+R2
= 103mV +I
IN 43.6Ω
IIN is IIN– or IIN+.The transimpedance in this example is
50.4Ω.
Evaluating the LT6600-10
The low impedance levels and high frequency operation
of the LT6600-10 require some attention to the matching
networks between the LT6600-10 and other devices. The
previous examples assume an ideal (0Ω) source impedance
andalarge(1kΩ)loadresistance.Amongpracticalexamples
where impedance must be considered is the evaluation
of the LT6600-10 with a network analyzer. Figure 5
is a laboratory setup that can be used to characterize the
LT6600-10 using single-ended instruments with 50Ω
source impedance and 50Ω input impedance. For a unity
gain conguration the LT6600-10 requires a 402Ω source
resistance yet the network analyzer output is calibrated
for a 50Ω load resistance. The 1:1 transformer, 53.6Ω
and 388Ω resistors satisfy the two constraints above.
The transformer converts the single-ended source into a
differential stimulus. Similarly, the output the LT6600-10
will have lower distortion with larger load resistance yet
the analyzer input is typically 50Ω. The 4:1 turns (16:1
impedance) transformer and the two 402Ω resistors of
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