参数资料
型号: LT6600IS8-2.5#PBF
厂商: Linear Technology
文件页数: 16/16页
文件大小: 0K
描述: IC AMP DIFF LP FLTR 2.5MHZ 8SOIC
标准包装: 100
放大器类型: 差分
电路数: 1
输出类型: 差分
电流 - 输入偏压: 15µA
电压 - 输入偏移: 5000µV
电流 - 电源: 28mA
电压 - 电源,单路/双路(±): 3 V ~ 11 V,±1.5 V ~ 5.5 V
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 8-SOIC(0.154",3.90mm 宽)
供应商设备封装: 8-SO
包装: 管件
LT6600-2.5
9
660025fe
APPLICATIONS INFORMATION
Use Figure 4 to determine the interface between the
LT6600-2.5 and a current output DAC. The gain, or “trans-
impedance,” is dened as A = VOUT/IIN. To compute the
transimpedance, use the following equation:
A =
1580 R1
R1+ R2
()
Ω
()
By setting R1 + R2 = 1580Ω, the gain equation reduces
to A = R1(Ω).
The voltage at the pins of the DAC is determined by R1,
R2, the voltage on VMID and the DAC output current.
Consider Figure 4 with R1 = 49.9Ω and R2 = 1540Ω. The
voltage at VMID, for VS = 3.3V, is 1.65V. The voltage at the
DAC pins is given by:
V
DAC = VPIN7
R1
R1+ R2 + 1580
+IIN
R1 R2
R1+ R2
= 26mV +IIN 48.3Ω
IIN is IIN+ or IIN–. The transimpedance in this example is
49.6Ω.
Evaluating the LT6600-2.5
The low impedance levels and high frequency operation
of the LT6600-2.5 require some attention to the matching
networks between the LT6600-2.5 and other devices. The
previous examples assume an ideal (0Ω) source imped-
ance and a large (1kΩ) load resistance. Among practical
examples where impedance must be considered is the
evaluation of the LT6600-2.5 with a network analyzer.
Figure 5 is a laboratory setup that can be used to charac-
terize the LT6600-2.5 using single-ended instruments
with 50Ω source impedance and 50Ω input impedance.
For a 12dB gain conguration the LT6600-2.5 requires a
402Ω source resistance yet the network analyzer output is
calibrated for a 50Ω load resistance. The 1:1 transformer,
53.6Ω and 388Ω resistors satisfy the two constraints
above. The transformer converts the single-ended source
into a differential stimulus. Similarly, the output of the
LT6600-2.5 will have lower distortion with larger load
resistance yet the analyzer input is typically 50Ω. The 4:1
turns (16:1 impedance) transformer and the two 402Ω
resistors of Figure 5, present the output of the LT6600-2.5
with a 1600Ω differential load, or the equivalent of 800Ω
to ground at each output. The impedance seen by the
network analyzer input is still 50Ω, reducing reections in
the cabling between the transformer and analyzer input.
Differential and Common Mode Voltage Ranges
The rail-to-rail output stage of the LT6600-2.5 can process
large differential signal levels. On a 3V supply, the output
signal can be 5.1VP-P. Similarly, a 5V supply can support
signals as large as 8.8VP-P. To prevent excessive power
dissipation in the internal circuitry, the user must limit
differential signal levels to 9VP-P.
The two ampliers inside the LT6600-2.5 have indepen-
dent control of their output common mode voltage (see
the Block Diagram section). The following guidelines will
optimize the performance of the lter.
Figure 4. (S8 Pin Numbers)
Figure 5. (S8 Pin Numbers)
+
0.1μF
3.3V
+
LT6600-2.5
3
4
1
0.01μF
CURRENT
OUTPUT
DAC
7
2
8
5
VOUT
+
VOUT
660025 F04
6
R2
R1
IIN
IIN
+
R2
R1
=
VOUT
+ – VOUT–
IIN
+ – IIN–
1580 R1
R1 + R2
+
0.1μF
2.5V
–2.5V
+
LT6600-2.5
3
4
1
7
2
8
5
6
660025 F05
402Ω
NETWORK
ANALYZER
INPUT
50Ω
COILCRAFT
TTWB-16A
4:1
NETWORK
ANALYZER
SOURCE
COILCRAFT
TTWB-1010
1:1
50Ω
53.6Ω
388Ω
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