参数资料
型号: LTC3401EMS#TR
厂商: Linear Technology
文件页数: 11/16页
文件大小: 0K
描述: IC REG BOOST SYNC ADJ 1A 10MSOP
标准包装: 2,500
类型: 升压(升压)
输出类型: 可调式
输出数: 1
输出电压: 2.6 V ~ 5.5 V
输入电压: 0.5 V ~ 5.5 V
PWM 型: 电流模式,混合
频率 - 开关: 3MHz
电流 - 输出: 1A
同步整流器:
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 10-TFSOP,10-MSOP(0.118",3.00mm 宽)
包装: 带卷 (TR)
供应商设备封装: 10-MSOP
其它名称: LTC3401EMSTR
LTC3401
APPLICATIO S I FOR ATIO
R 6 ≈ ? FF IN
? V OUT OUT ?
? Δ I
f FILTERZERO =
A logic level feed forward signal, V FF , is coupled through
components C5 and R6. The amount of feed forward
signal is attenuated with resistor R6 and is given by the
following relationship:
? V ? R 5 ? V ? 1 . 5 ?
? – R 5
where Δ I OUT = load current change.
where C OUT is the output filter capacitor.
The output filter zero is given by:
1
Hz
2 ? π ? R ESR ? C OUT
where R ESR is the capacitor equivalent series resistance.
A troublesome feature of the boost regulator topology is
the right half plane zero (RHP) and is given by:
V IN
3
V IN
LTC3401
SW
4
V OUT
f RHPZ =
V IN 2 ? R O
2 ? π ? L ? V O 2
Hz
10
SHDN
V OUT
7
At heavy loads this gain increase with phase lag can occur
2
6
1
MODE/SYNC FB
PGOOD V C
R t GND
8
9
5
C3
at a relatively low frequency. The loop gain is typically
rolled off before the RHP zero frequency.
The typical error amp compensation is shown in Figure 4.
The equations for the loop dynamics are as follows:
R5
LOAD FEED
V FF
f POLE 1 ≈
f ZERO 1 =
C5
3.3nF
R6
FORWARD
SIGNAL
Figure 3
Closing the Feedback Loop
3404 F03
1
Hz
2 ? π ? 20 ? 10 6 ? C C 1
which is extremelyclose to DC
1
Hz
2 ? π ? R Z ? C C 1
The LTC3401 uses current mode control with internal
adaptive slope compensation. Current mode control elimi-
f POLE 2 ≈
1
2 ? π ? R Z ? C C 2
Hz
nates the 2nd order filter due to the inductor and output
capacitor exhibited in voltage mode controllers, and sim-
V OUT
plifies it to a single-pole filter response. The product of the
modulator control to output DC gain plus the error amp
open-loop gain equals the DC gain of the system.
G DC = G CONTROLOUTPUT ? G EA
+
ERROR
AMP
1.25V
FB
8
V C
9
C C1
C C2
R1
R2
G CONTROL =
2 ? V IN
I OUT
, G EA ≈ 2000
R Z
3401 F04
The output filter pole is given by:
Figure 4
f FILTERPOLE =
I OUT
π ? V OUT ? C OUT
Hz
Refer to Application Note AN-76 for more closed loop
examples.
3401fb
11
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