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参数资料
| 型号： | LTC3775EUD#PBF |
| 厂商： | Linear Technology |
| 文件页数： | 11/34页 |
| 文件大小： | 0K |
| 描述： | IC REG CTRLR BUCK PWM VM 16-QFN |
| 标准包装： | 121 |
| PWM 型： | 电压模式 |
| 输出数： | 1 |
| 频率 - 最大： | 1MHz |
| 占空比： | 80% |
| 电源电压： | 4.5 V ~ 38 V |
| 降压： | 是 |
| 升压： | 无 |
| 回扫： | 无 |
| 反相： | 无 |
| 倍增器： | 无 |
| 除法器： | 无 |
| Cuk： | 无 |
| 隔离： | 无 |
| 工作温度： | -40°C ~ 85°C |
| 封装/外壳： | 16-WFQFN 裸露焊盘 |
| 包装： | 管件 |
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LTC3775
APPLICATIONS INFORMATION
V COMP – ( 1 + sR2C1 ) 1 + s(R A + R3)C3
V OUT
sR A ( ) ( ) ( 1 + sC3R3 )
C1 + C2 1 + s(C1|| C2)R2
f C
f C
– 20log ( A MOD )
Figure1showsaType3ampli?er.Thetransferfunctionof
this ampli?er is given by the following equation:
=
The RC network across the error ampli?er and the feed-
Required error ampli?er gain at frequency f C :
A V(CROSSOVER)
2 2
40log 1 + – 20log 1 +
f LC f ESR
1 + P2(RES) + P2(RES)
f LC
f C
1 + P2(RES)
f ESR
f ESR – f LC
f C
forward components R3 and C3 introduce two pole-zero
pairs to obtain a phase boost at the system unity-gain
frequency, f C . In theory, the zeros and poles are placed
symmetrically around f C , and the spread between the zeros
and the poles is adjusted to give the desired phase boost
at f C . However, in practice, if the crossover frequency
20log
R2
R A
?
1 +
f LC
f C
1 +
f f – f Z2(RES)
+
f C f Z2(RES)
f
V SAW
is much higher than the LC double-pole frequency, this
method of frequency compensation normally generates
a phase dip within the unity bandwidth and creates some
concern regarding conditional stability.
If conditional stability is a concern, move the error ampli-
?er’s zero to a lower frequency to avoid excessive phase
dip. The following equations can be used to compute the
feedback compensation component values:
f SW = switching frequency
where A MOD is the modulator and line feedforward gain
and is equal to:
V IN(MAX ) ? DC MAX 40 V ? 0 . 95
A MOD ≈ = ≈ 30 V / V
1 . 25 V
Once the value of resistor R A and the pole and zero loca-
tions have been decided, the values of C1, R2, C2, R3 and
C3 can be obtained from the above equations.
Compensating a switching power supply feedback loop is
f LC =
1
2 π LC OUT
a complex task. The applications shown in this data sheet
show typical values, optimized for the power components
shown. Though similar power components should suf?ce,
2 π R E SR OUT
f ESR =
choose:
1
C
substantially changing even one major power component
may degrade performance signi?cantly. Stability also may
depend on circuit board layout. To verify the calculated
component values, all new circuit designs should be
f C = crossover frequency =
f SW
10
prototyped and tested for stability.
C2
V OUT
f Z 1( ERR ) = f LC =
1
2 π R 2 C 1
R A
C3
R3
R2
C1
0
GAIN
–1
+1
–1
FREQ
f C 1
(
)
f Z 2 ( RES ) = =
2 π R A + R 3 C 3
f P 1 ( ERR ) = f ESR =
5
1
2 π R 2 ( C 1 || C 2 )
R B
V REF
FB
COMP
PHASE
BOOST
Figure 1. Type 3 Ampli?er Compensation
–90
–180
–270
–380
3775 F01
f P 2 ( RES ) = 5 f C =
1
2 π R 3 C 3
3775fa
11
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