参数资料
型号: M34513E4SP
元件分类: 微控制器/微处理器
英文描述: 4-BIT, OTPROM, 4.2 MHz, MICROCONTROLLER, PDIP32
封装: 0.400 INCH, 1.78 MM PITCH, PLASTIC, SDIP-32
文件页数: 74/97页
文件大小: 1276K
代理商: M34513E4SP
Skip condition
Datailed description
Carry
flag
CY
75
4513/4514 Group
SINGLE-CHIP 4-BIT CMOS MICROCOMPUTER
MITSUBISHI MICROCOMPUTERS
When bit 2 (I12) of register I1 is “1” : Skips the next instruction when the level of INT0 pin is “H.”
When bit 2 (I12) of register I1 is “0” : Skips the next instruction when the level of INT0 pin is “L.”
When bit 2 (I22) of register I2 is “1” : Skips the next instruction when the level of INT1 pin is “H.”
When bit 2 (I22) of register I2 is “0” : Skips the next instruction when the level of INT1 pin is “L.”
Transfers the contents of interrupt control register V1 to register A.
Transfers the contents of register A to interrupt control register V1.
Transfers the contents of interrupt control register V2 to register A.
Transfers the contents of register A to interrupt control register V2.
Transfers the contents of interrupt control register I1 to register A.
Transfers the contents of register A to interrupt control register I1.
Transfers the contents of interrupt control register I2 to register A.
Transfers the contents of register A to interrupt control register I2.
Transfers the contents of timer control register W1 to register A.
Transfers the contents of register A to timer control register W1.
Transfers the contents of timer control register W2 to register A.
Transfers the contents of register A to timer control register W2.
Transfers the contents of timer control register W3 to register A.
Transfers the contents of register A to timer control register W3.
Transfers the contents of timer control register W4 to register A.
Transfers the contents of register A to timer control register W4.
Transfers the contents of timer control register W6 to register A.
Transfers the contents of register A to timer control register W6.
(INT0) = “H”
However, I12 = 1
(INT0) = “L”
However, I12 = 0
(INT1) = “H”
However, I22 = 1
(INT1) = “L”
However, I22 = 0
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