参数资料
型号: MAX5003ESE+T
厂商: Maxim Integrated Products
文件页数: 12/16页
文件大小: 0K
描述: IC REG CTRLR FLYBK ISO VM 16SOIC
产品培训模块: Lead (SnPb) Finish for COTS
Obsolescence Mitigation Program
标准包装: 2,500
PWM 型: 电压模式
输出数: 1
频率 - 最大: 1.2MHz
占空比: 75%
电源电压: 11 V ~ 110 V
降压:
升压:
回扫:
反相:
倍增器:
除法器:
Cuk:
隔离:
工作温度: -40°C ~ 85°C
封装/外壳: 16-SOIC(0.154",3.90mm 宽)
包装: 带卷 (TR)
High-Voltage PWM
Power-Supply Controller
+48V
V IN
(36V TO 72V)
XFACOILTRCTX03
2
8
1M
L P
65 μ H
CMSD4448
4.7 μ F
1
V+
V DD
16
5
7
2
3
INDIV
ES
V CC
NDRV
15
14
IRFD620S
11, 12
MBRS130L
+5V
1A
0.1 μ F
4
5
6
7
8
MAX5003
FREQ
PGND
SS CS
REF AGND
CON MAXTON
COMP FB
13
12
11
10
9
10 μ F
33 μ F
100 ?
0.1 μ F
9, 10
22 μ F
22 μ F
R A
41.2k
39k
62k
51k
0.1 μ F
470nF
0.1 μ F
C F
390pF
R F
200k
R CS
0.1 ?
R B
17.4k
0V
Figure 2. Application Example 1: Nonisolated +48V to +5V Converter
DC MAX =
? ?
? + 1
?
( DC × V MIN ) ( V )
3) The main factors influencing the choice of the turns
ratio are the switch breakdown voltage and the duty
cycle. With a smaller turns ratio, the secondary
reflected voltage and the maximum voltage seen by
the switch during flyback are reduced, which is
favorable. On the other hand, a smaller turns ratio
will shorten the duty cycle and increase the primary
RMS current, which can impact efficiency. A good
starting figure is the ratio of the input voltage to the
output voltage, rounding to the nearest integer. To
keep the flyback voltage under control, choose an 8-
to-1 ratio for the 48V to 5V system. The maximum
duty cycle allowed without putting the device in con-
tinuous-conduction mode can be found using the fol-
lowing formula:
1
V MIN
? V SEC × N ?
where:
N = N P /N S = Turns ratio
V SEC = Secondary voltage
DC MAX = Maximum duty cycle
V MIN = Minimum power-line voltage
For a 48V to 5V system with an 8-to-1 turns ratio, the
maximum duty cycle before putting the device in
discontinuous mode is 55%. Assume that V IN min is
36V (minimum input voltage, neglecting drops in the
power switch and in the resistance of the primary
coil) and V SEC is 5.4V (5V plus a Schottky diode
drop). The MAX5003 maximum duty cycle is internal-
ly limited to 75%. Generally this parameter must fall
between 45% to 65% to obtain a balance between
efficiency and flyback voltage while staying out of
continuous conduction. If the value exceeds these
bounds, adjust the turns ratio.
4) Assuming 80% efficiency, a 6.25W input is needed
to produce a 5W output. Set an operating duty cycle
around 12% below the maximum duty cycle to allow
for component variation: 55% - 12% = 43%. Use the
following formula to calculate the primary inductance:
2 2
0 . 43 × 36
L PRI = = ? 65 μ H
2 × PWR IN × ? SW 2 × 6 . 25 W × 300 kHz
12
______________________________________________________________________________________
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