参数资料
| 型号： | MC14538BFG |
| 厂商： | ON Semiconductor |
| 文件页数： | 8/14页 |
| 文件大小： | 0K |
| 描述： | IC MULTIVIBRATOR DUAL 16SOEIAJ |
| 标准包装： | 50 |
| 系列： | 4000B |
| 逻辑类型： | 单稳态 |
| 独立电路： | 2 |
| 施密特触发器输入： | 无 |
| 传输延迟： | 95ns |
| 输出电流高，低： | 8.8mA，8.8mA |
| 电源电压： | 3 V ~ 18 V |
| 工作温度： | -55°C ~ 125°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 16-SOIC（0.209"，5.30mm 宽） |
| 供应商设备封装： | 16-SOEIAJ |
| 包装： | 管件 |
| 其它名称： | MC14538BFG-ND MC14538BFGOS |
MC14538B
http://onsemi.com
3
ELECTRICAL CHARACTERISTICS (Voltages Referenced to VSS)
Characteristic
Symbol
VDD
Vdc
55_C
25_C
125_C
Unit
Min
Max
Min
Typ
(Note 2)
Max
Min
Max
Output Voltage
“0” Level
Vin = VDD or 0
VOL
5.0
10
15
0.05
0
0.05
0.05
Vdc
“1” Level
Vin = 0 or VDD
VOH
5.0
10
15
4.95
9.95
14.95
4.95
9.95
14.95
5.0
10
15
4.95
9.95
14.95
Vdc
Input Voltage
“0” Level
(VO = 4.5 or 0.5 Vdc)
(VO = 9.0 or 1.0 Vdc)
(VO = 13.5 or 1.5 Vdc)
VIL
5.0
10
15
1.5
3.0
4.0
2.25
4.50
6.75
1.5
3.0
4.0
1.5
3.0
4.0
Vdc
“1” Level
(VO = 0.5 or 4.5 Vdc)
(VO = 1.0 or 9.0 Vdc)
(VO = 1.5 or 13.5 Vdc)
VIH
5.0
10
15
3.5
7.0
11
3.5
7.0
11
2.75
5.50
8.25
3.5
7.0
11
Vdc
Output Drive Current
(VOH = 2.5 Vdc)
Source
(VOH = 4.6 Vdc)
(VOH = 9.5 Vdc)
(VOH = 13.5 Vdc)
IOH
5.0
10
15
– 3.0
– 0.64
– 1.6
– 4.2
– 2.4
– 0.51
– 1.3
– 3.4
– 4.2
– 0.88
– 2.25
– 8.8
– 1.7
– 0.36
– 0.9
– 2.4
mAdc
(VOL = 0.4 Vdc)
Sink
(VOL = 0.5 Vdc)
(VOL = 1.5 Vdc)
IOL
5.0
10
15
0.64
1.6
4.2
0.51
1.3
3.4
0.88
2.25
8.8
0.36
0.9
2.4
mAdc
Input Current, Pin 2 or 14
Iin
15
±0.05
±0.00001
±0.05
±0.5
mAdc
Input Current, Other Inputs
Iin
15
±0.1
±0.00001
±0.1
±1.0
mAdc
Input Capacitance, Pin 2 or 14
Cin
25
pF
Input Capacitance, Other Inputs
(Vin = 0)
Cin
5.0
7.5
pF
Quiescent Current
(Per Package)
Q = Low, Q = High
IDD
5.0
10
15
5.0
10
20
0.005
0.010
0.015
5.0
10
20
150
300
600
mAdc
Quiescent Current, Active State
(Both) (Per Package)
Q = High, Q = Low
IDD
5.0
10
15
2.0
0.04
0.08
0.13
0.20
0.45
0.70
2.0
mAdc
Total Supply Current at an external
load capacitance (CL) and at
external timing network (RX, CX)
(Note 3)
IT
5.0
10
IT = (3.5 x 10–2) RXCXf + 4CXf + 1 x 10–5 CLf
IT = (8.0 x 10–2) RXCXf + 9CXf + 2 x 10–5 CLf
IT = (1.25 x 10–1) RXCXf + 12CXf + 3 x 10–5 CLf
where: IT in mA (one monostable switching only),
where: CX in mF, CL in pF, RX in k ohms, and
where: f in Hz is the input frequency.
mAdc
2. Data labelled “Typ” is not to be used for design purposes but is intended as an indication of the IC’s potential performance.
3. The formulas given are for the typical characteristics only at 25_C.
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