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| 型号： | PACDN009MR |
| 厂商： | ON Semiconductor |
| 文件页数： | 4/7页 |
| 文件大小： | 0K |
| 描述： | IC ESD ARRAY PROT 5-CH 8MSOP |
| 标准包装： | 4,000 |
| 电压 - 反向隔离（标准值）： | 5.5V |
| 电压 - 击穿： | 6V |
| 电极标记： | 5 通道阵列 - 双向 |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 8-TSSOP，8-MSOP（0.118"，3.00mm 宽） |
| 供应商设备封装： | 8-MSOP |
| 包装： | 带卷 (TR) |
PACDN009
PERFORMANCE INFORMATION
Input Capacitance vs. Input Voltage
Figure 1. Typical Variation of C IN vs. V IN
(V P = 5 V, V N = 0 V, 0.1 m F Chip Capacitor between V P and V N )
APPLICATION INFORMATION
Design Considerations
In order to realize the maximum protection against ESD pulses, care must be taken in the PCB layout to minimize parasitic
series inductances on the Supply/Ground rails as well as the signal trace segment between the signal input (typically
a connector) and the ESD protection device. Refer to Figure 2, which illustrates an example of a positive ESD pulse striking
an input channel. The parasitic series inductance back to the power supply is represented by L 1 and L 2 . The voltage V CL on
the line being protected is:
V CL + Fwd Voltage Drop of D 1 ) V SUPPLY ) L 1
d ( I ESD ) dt ) L 2
d ( I ESD ) dt
where I ESD is the ESD current pulse, and V SUPPLY is the positive supply voltage.
An ESD current pulse can rise from zero to its peak value in a very short time. As an example, a level 4 contact discharge
per the IEC61000 ? 4 ? 2 standard results in a current pulse that rises from zero to 30 Amps in 1 ns. Here d(I ESD )/dt can be
approximated by D I ESD / D t, or 30/(1x10 ? 9 ). So just 10 nH of series inductance (L 1 and L 2 combined) will lead to a 300 V
increment in V CL !
Similarly for negative ESD pulses, parasitic series inductance from the V N pin to the ground rail will lead to drastically
increased negative voltage on the line being protected.
Another consideration is the output impedance of the power supply for fast transient currents. Most power supplies exhibit
a much higher output impedance to fast transient current spikes. In the V CL equation above, the V SUPPLY term, in reality, is
given by (V DC + I ESD x R OUT ), where V DC and R OUT are the nominal supply DC output voltage and effective output impedance
of the power supply respectively. As an example, a R OUT of 1 W would result in a 10 V increment in V CL for a peak I ESD of
10 A.
If the inductances and resistance described above are close to zero, the rail ? clamp ESD protection diodes will do a good job
of protection. However, since this is not possible in practical situations, a bypass capacitor must be used to absorb the very high
frequency ESD energy. So for any brand of rail ? clamp ESD protection diodes, a bypass capacitor should be connected between
the V P pin of the diodes and the ground plane (V N pin of the diodes) as shown in the Application Circuit diagram below. A value
of 0.22 m F is adequate for IEC ? 61000 ? 4 ? 2 level 4 contact discharge protection ( ? 8 kV). Ceramic chip capacitors mounted with
short printed circuit board traces are good choices for this application. Electrolytic capacitors should be avoided as they have
poor high frequency characteristics. For extra protection, connect a zener diode in parallel with the bypass capacitor to mitigate
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