参数资料
型号: PIC18F67K90T-I/PTRSL
厂商: Microchip Technology
文件页数: 48/110页
文件大小: 0K
描述: MCU 8BIT 128K FLASH 64-TQFP
标准包装: 1,200
系列: PIC® XLP™ 18F
核心处理器: PIC
芯体尺寸: 8-位
速度: 64MHz
连通性: I²C,LIN,SPI,UART/USART
外围设备: 欠压检测/复位,LCD,POR,PWM,WDT
输入/输出数: 53
程序存储器容量: 128KB(64K x 16)
程序存储器类型: 闪存
EEPROM 大小: 1K x 8
RAM 容量: 4K x 8
电压 - 电源 (Vcc/Vdd): 1.8 V ~ 5.5 V
数据转换器: A/D 16x12b
振荡器型: 内部
工作温度: -40°C ~ 85°C
封装/外壳: 64-TQFP
包装: 带卷 (TR)
2010 Microchip Technology Inc.
Preliminary
DS39964B-page 495
PIC18F47J53 FAMILY
SUBLW
Subtract W from Literal
Syntax:
SUBLW k
Operands:
0
k 255
Operation:
k – (W)
W
Status Affected:
N, OV, C, DC, Z
Encoding:
0000
1000
kkkk
Description:
W is subtracted from the eight-bit
literal ‘k’. The result is placed in W.
Words:
1
Cycles:
1
Q Cycle Activity:
Q1
Q2
Q3
Q4
Decode
Read
literal ‘k’
Process
Data
Write to
W
Example 1:
SUBLW
02h
Before Instruction
W
=
01h
C=
?
After Instruction
W
=
01h
C=
1
; result is positive
Z=
0
N=
0
Example 2:
SUBLW
02h
Before Instruction
W
=
02h
C=
?
After Instruction
W
=
00h
C=
1
; result is zero
Z=
1
N=
0
Example 3:
SUBLW
02h
Before Instruction
W
=
03h
C=
?
After Instruction
W
=
FFh
; (2’s complement)
C=
0
; result is negative
Z=
0
N=
1
SUBWF
Subtract W from f
Syntax:
SUBWF
f {,d {,a}}
Operands:
0
f 255
d
[0,1]
a
[0,1]
Operation:
(f) – (W)
dest
Status Affected:
N, OV, C, DC, Z
Encoding:
0101
11da
ffff
Description:
Subtract W from register ‘f’ (2’s
complement method). If ‘d’ is ‘0’, the
result is stored in W. If ‘d’ is ‘1’, the result
is stored back in register ‘f’ (default).
If ‘a’ is ‘0’, the Access Bank is selected.
If ‘a’ is ‘1’, the BSR is used to select the
GPR bank (default).
If ‘a’ is ‘0’ and the extended instruction
set is enabled, this instruction operates
in Indexed Literal Offset Addressing
mode whenever f
95 (5Fh). See
Words:
1
Cycles:
1
Q Cycle Activity:
Q1
Q2
Q3
Q4
Decode
Read
register ‘f’
Process
Data
Write to
destination
Example 1:
SUBWF
REG, 1, 0
Before Instruction
REG
=
3
W=
2
C=
?
After Instruction
REG
=
1
W=
2
C
=
1
; result is positive
Z=
0
N=
0
Example 2:
SUBWF
REG, 0, 0
Before Instruction
REG
=
2
W=
2
C=
?
After Instruction
REG
=
2
W=
0
C
=
1
; result is zero
Z=
1
N=
0
Example 3:
SUBWF
REG, 1, 0
Before Instruction
REG
=
1
W=
2
C=
?
After Instruction
REG
=
FFh ;(2’s complement)
W=
2
C
=
0
; result is negative
Z=
0
N=
1
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