参数资料
型号: RC0201-R-SKE24L
厂商: Yageo
文件页数: 3/16页
文件大小: 0K
描述: RES KIT 0201
标准包装: 1
系列: RC0201
套件类型: 1/20W(.05W)1%、5% 厚膜
安装类型: 表面贴装
包括封装: 0201(0603 公制)
工具箱内容: (100) 311-68KNCT-ND - RES 68K OHM 1/20W 5% 0201 SMD
(100) 311-680NCT-ND - RES 680 OHM 1/20W 5% 0201 SMD
(100) 311-5.6KNCT-ND - RES 5.6K OHM 1/20W 5% 0201 SMD
(100) 311-560NCT-ND - RES 560 OHM 1/20W 5% 0201 SMD
(100) 311-51NCT-ND - RES 51 OHM 1/20W 5% 0201 SMD
(100) 311-51KNCT-ND - RES 51K OHM 1/20W 5% 0201 SMD
(100) 311-4.7KNCT-ND - RES 4.7K OHM 1/20W 5% 0201 SMD
(100) 311-47NCT-ND - RES 47 OHM 1/20W 5% 0201 SMD
(100) 311-47KNCT-ND - RES 47K OHM 1/20W 5% 0201 SMD
(100) 311-470NCT-ND - RES 470 OHM 1/20W 5% 0201 SMD
更多...
其它名称: Q4761638
Product specification
3
Chip Resistor Surface Mount
Thick film technology
INTRODUCTION
16
S U M M A R I Z I N G
is the reciprocal of the heat resistance and is the
Description
Dimensions, conductance of materials and
mounting determine
Heat resistance × dissipation gives
Temperature rise + ambient temperature give
Relationship
heat resistance
temperature rise
hot-spot
temperature
characteristic for the resistor and its environment.
T H E T E M P E R A T U R E C O E F F I C I E N T
The temperature coefficient of resistance is a ratio
which indicates the rate of increase (decrease) of
resistance per degree (°C) increase (decrease) of
temperature within a specified range, and is
expressed in parts per million per °C (ppm/°C).
T m ? T amb
P E R F O R M A N C E
When specifying the performance of a resistor, the
dissipation is given as a function of the hot-spot
temperature, with the ambient temperature as a
parameter.
From ? T = A × P and T m = T amb ? ? T it follows
that:
P ?
A
If P is plotted against Tm for a constant value of A,
parallel straight lines are obtained for different
values of the ambient temperature. The slope of
these lines,
E XAMPLE
If the temperature coefficient of a resistor of
R nom = 1 k X between –55 °C and +155 °C is ±200
ppm/°C, its resistance will be:
at 25 °C:
1,000 X (nominal = rated value)
at +155 °C:
1,000 X ±(130 × 200 ppm/°C) × 1,000 X
= 1,026 X or 974 X
at –55 °C:
1,000 X ±(80 × 200 ppm/°C) × 1,000 X
= 1,016 X or 984 X
If the temperature coefficient is specified as ≤ 200
dP
dT m
?
I
A
ppm/°C the resistance will be within the shaded area
as shown in Fig. 1.
handbook, full pagewidth
2.6%
1.6%
26 Ω
T ( C)
R nom
55
0
2 5
o
155
1.6%
16 Ω
2.6%
MGA208
Fig. 1 Temperature coefficient.
www.yageo.com
Mar 25, 2008 V.7
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