参数资料
型号: TPA0103PWPG4
厂商: TEXAS INSTRUMENTS INC
元件分类: 音频/视频放大
英文描述: 2.1 W, 3 CHANNEL, AUDIO AMPLIFIER, PDSO24
封装: GREEN, PLASTIC, HTSSOP-24
文件页数: 22/43页
文件大小: 1123K
代理商: TPA0103PWPG4
TPA0103
1.75-W 3-CHANNEL STEREO AUDIO POWER AMPLIFIER
SLOS167A – JULY 1997 – REVISED MARCH 2000
29
POST OFFICE BOX 655303
DALLAS, TEXAS 75265
APPLICATION INFORMATION
gain setting resistors, RF and RI
The gain for each audio input of the TPA0103 is set by resistors RF and RI according to equation 5 for BTL mode.
(5)
BTL Gain
+ * 2
R
F
R
I
In SE mode the gain is set by the RF and RI resistors and is shown in equation 6. Since the inverting amplifier
is not used to mirror the voltage swing on the load, the factor of 2, from equation 5, is not included.
(6)
SE Gain
+*
R
F
R
I
BTL mode operation brings about the factor 2 in the gain equation due to the inverting amplifier mirroring the
voltage swing across the load. Given that the TPA0103 is a MOS amplifier, the input impedance is very high,
consequently input leakage currents are not generally a concern although noise in the circuit increases as the
value of RF increases. In addition, a certain range of RF values are required for proper startup operation of the
amplifier. Taken together it is recommended that the effective impedance seen by the inverting node of the
amplifier be set between 5 k
and 20 k. The effective impedance is calculated in equation 7.
(7)
Effective Impedance
+
R
FRI
R
F ) RI
As an example consider an input resistance of 10 k
and a feedback resistor of 50 k. The BTL gain of the
amplifier would be –10 and the effective impedance at the inverting terminal would be 8.3 k
, which is well within
the recommended range.
For high performance applications metal film resistors are recommended because they tend to have lower noise
levels than carbon resistors. For values of RF above 50 k the amplifier tends to become unstable due to a pole
formed from RF and the inherent input capacitance of the MOS input structure. For this reason, a small
compensation capacitor of approximately 5 pF should be placed in parallel with RF when RF is greater than
50 k
. This, in effect, creates a low pass filter network with the cutoff frequency defined in equation 8.
(8)
f
c(lowpass) +
1
2
pR
F
C
F
–3 dB
fc
For example, if RF is 100 k and Cf is 5 pF then fc is 318 kHz, which is well outside of the audio range.
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TPA0103PWPRG4 2.1 W, 3 CHANNEL, AUDIO AMPLIFIER, PDSO24
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