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| 型号： | TPS40131RHBTG4 |
| 厂商： | TEXAS INSTRUMENTS INC |
| 元件分类： | 稳压器 |
| 英文描述： | SWITCHING CONTROLLER, 1200 kHz SWITCHING FREQ-MAX, PQCC32 |
| 封装： | GREEN, PLASTIC, QFN-32 |
| 文件页数： | 17/40页 |
| 文件大小： | 940K |
| 代理商： | TPS40131RHBTG4 |
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fESR
OUT
1
176.8 kHz
2
C
ESR
=
p
(45)
+
C2
R2
R3
C1
V
REF
C3
R1
(
)
(
)
(
)
(
) (
)
(
)
C(s)
s
R1
R3
C1
1
s
R2
C2
1
G
C2
C3
R1
C2
C3
s
R3
C1
1
s
R2
1
C2
C3
+
+
+
÷
=
÷
+
è
+
+
÷
÷
+
è
è
(46)
V(s)
C(s)
VC(s)
T
G
=
(47)
f
P1
ESR
1
2
R3
C1
=
p
(48)
f
P2
SW
1
C2
C3
2
R2
C2
C3
=
p
÷
+
è
(49)
f
Z1
VCP1
1
2
R2
C2
=
p
(50)
(
)
f
Z 2
VCP 2
1
2
R1
R3
C1
=
p
+
(51)
f
V
C
T ( j
2
)
1
p
=
(52)
(
)
( )
4
CM
1
A
2.09
10
R1
C2
C3
=
÷
÷
+
è
(53)
SLVS635 – FEBRUARY 2007
The ESR zero is calculated in Equation 45.
In this design, a Type III compensator is employed to compensate the loop.
Figure 9. Type III Compensator
The compensator transfer function is shown in Equation 46.
The loop gain transfer function is shown in Equation 47.
Assume the desired crossover frequency is 20 kHz. Place one zero at fVCP1 and another zero at fVCP2, then
place one pole at fESRand another pole at fSW. The compensator gain is then calculated to achieve the desired
bandwidth. In this design, the compensator gain, pole and zero are selected using the following equations:
From Equation 52 the compensator gain is solved as 2.09
×104.
Set R1 equal to 10 k
, and then calculate all the other components.
24
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