参数资料
型号: 1.1001
元件分类: 保险丝
英文描述: Fuse
中文描述: 保险丝
文件页数: 54/65页
文件大小: 2586K
代理商: 1.1001
Schurter, Inc. Phone 707-778-6311 Fax 707-778-6401 E-mail: info@schurterinc.com Website http://www.schurterinc.com
160
Surge Tolerant Fuses
Testing: Introduction
Several standards have been established for the Telecom
industry, all of which are aimed at combining the interference
influences of Lightning Surge, Power Induction and Power
Contact, together with the associated safety aspects, and to
derive suitable testing methods for the components
in question.
Various kinds of loads have been defined and standardised
as testing criteria. They can be simulated with the aid of an
appropriate test circuit. This provides circuit designers with the
facility for optimally adapting the stages of a protection circuit to
one another.
Current relevant standards are:
ITU-T K.20
International Telecommunication Union,
Standardisation Sector of ITU
UL 1459/1950
Standard for Safety, Telephone Equipment
(USA)
GR 1089 Core
Bell Communications Research (USA)
Tests :
Schurter fuses have been tested according to the following
standards and testing criteria(this list is not exhaustive):
1. ITU-T K.20
Lightning Surge: Test circuit
Fig. 1
Pulse current
Generator no-load
t
t1=10s
t2=700s
50%
I puls
max.
Ipuls
RD
U
c
=
1000
V
+
20 F
0,2 F
50
RM
15
Fuse
Test:
1. The pulse amplitude (generator no-load) is set to 1000 V
and the pulse shape to 10 s / 700 s.
2. The pulse current Ipuls is set to the value Ipuls max. stated in
the data sheet with limiting resistor RD.
3. Test mode : 10 single pulses, at an interval of 60 sec.
alternating polarity.
Requirement: The fuse shall not interrupt the circuit.
1) Note:
With a charge voltage of UC = 1000 V, the standardized
pulse generator in Fig. 1 supplies a maximum pulse current Ipuls
= 67 A, providing the current limiting resistor is
RD = 0. The shunt RM for the current monitoring has a very
low resistance and has therefore no notable influence to the
current amplitude. This means that the data sheet current
67 A (1) does not represent the maximum permissible pulse
amplitude of the fuse in question, but the maximum current
amplitude which can be supplied by the pulse generator. If a
max. current higher than 67 A is to be expected in a circuit, the
I2t-values of the fuse can be calculated using the formula I2t =
0,72 x i2peak x t2, as a good approximation in order that the
selected fuse can accept the expected current pulse without
interrupting the circuit.
Power induction: Test circuit
Fig. 2
Test: The fuse in the test circuit AC 300 V / 50 Hz is loaded 5
200 ms 60 s
200 ms
60 s
I eff = 0,5 A
600
Fuse
A
C
300
V
Fuse
A
C
250
V
RD
Isc
15 Min.
times with Ieff = 0,5 A for 200 ms at intervals of 60 sec.
Requirement: The fuse shall not interrupt the circuit.
Power Contact: Test circuit
Fig. 3
Test: The fuse in the test circuit AC 250 V / 50 Hz is loaded with
the current value ISC stated in the data sheet. The supply
voltage is maintained for 15 minutes.
Requirement: The fuse shall interrupt the circuit.
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