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参数资料
| 型号： | 1.1001 |
| 元件分类： | 保险丝 |
| 英文描述： | Fuse |
| 中文描述： | 保险丝 |
| 文件页数： | 55/65页 |
| 文件大小： | 2586K |
| 代理商： | 1.1001 |
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Schurter, Inc. Phone 707-778-6311 Fax 707-778-6401 E-mail: info@schurterinc.com Website http://www.schurterinc.com
161
Surge Tolerant Fuses
2. UL1459/1950
Test circuit
Fig. 4
Test 1:
The fuse in the test current circuit is loaded with a test current
of ISC = 40 A .
The AC 600 V / 50 Hz source voltage is applied for a total
of 1.5 sec.
Requirement: The fuse shall interrupt the circuit.
Test 2:
The fuse in the test current circuit is loaded with a test current
of ISC = 7 A .
The AC 600 V / 50 Hz source voltage is applied for a total
of 5 sec.
Requirement: The fuse shall interrupt the circuit.
Test 3
The fuse in the test current circuit is loaded with a test current
of ISC = 2,2 A .
The AC 600 V / 50Hz source voltage is applied for at least
30 minutes, or until stable thermal conditions are achieved
in the telecom unit or until the fuse interrupts the circuit.
This test is performed together with the equipment in which the
fuse is installed.
Fuse
A
C
600
V
RD
t = 1,5 s/5 s/ 30 Min.
I sc = 40 A/7 A/2.2. A
3. GR 1089
Test circuit
Test:
1. The pulse amplitude (generator no-load) is set to 1000 V
and the pulse shape to 10 s / 1000 s.
2. The pulse current Ipuls is set to the value Ipuls max. stated in
the data sheet with limiting resistor RD.
3. Test mode: 50 single pulses, at an interval of 60 sec.
alternating polarity.
Requirement: The fuse shall not interrupt the circuit.
5) Note: With a charge voltage of UC = 1000 V, the standar-
dized pulse generator in Fig. 5 supplies a maximum pulse
current Ipuls = 14 A, providing the current limiting resistor is
RD = 0. The shunt RM for the current monitoring has a very
low resistance and has no notable influence to the current
amplitude. This means that the data sheet current 14 A (5) does
not represent the maximum permissible pulse amplitude of the
fuse in question, but the maximum current amplitude which can
be supplied by the pulse generator. If a max. current higher
than 14 A is to be expected in a circuit, the
I2t- values of the fuse can be calculated using the formula I2t =
0,72 x i2peak x t2, as a good approximation in order that the
selected fuse can accept the expected current pulse without
interrupting the circuit.
Fig. 5
Pulse current
Generator no load
t1=10s
t2=1000s
50%
I puls
max.
Ipuls
RD
U
c
=
1000
V
.
+
20 F
267 H
50 k
RM
68
Fuse
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