参数资料
型号: A8509GLPTR-T
厂商: Allegro Microsystems Inc
文件页数: 21/28页
文件大小: 0K
描述: IC LED DVR WHITE 4X120MA 24TSSOP
标准包装: 8,000
拓扑: PWM,SEPIC,升压(升压)
输出数: 4
内部驱动器:
类型 - 主要: 背光
类型 - 次要: 白色 LED
频率: 300kHz ~ 800kHz
电源电压: 9 V ~ 40 V
安装类型: 表面贴装
封装/外壳: 24-TSSOP(0.173",4.40mm)裸露焊盘
供应商设备封装: 24-TSSOP 裸露焊盘
包装: 带卷 (TR)
工作温度: -40°C ~ 105°C
A8509
Wide Input Voltage Range, High Efficiency
4-Channel Fault Tolerant LED Driver
Design Example
This section provides a method for selecting component values
when designing an application using the A8509.
Assumptions: For the purposes of this example, the following are
given as the application requirements:
? V IN : 10 to 16 V
? Quantity of LED channels, #CHANNELS: 4
? Quantity of series LEDs per channel, #SERIESLEDS : 10
? LED current per channel, I LED : 240 mA
? V f(240) at 240 mA: 3.2 V (max)
? f SW : 600 kHz
? T A (max): 65°C
? PWM dimming frequency: 200 Hz, 1% duty cycle
Step 1: Connect LEDs to pins LED1 through LED4.
Electrical Characteristics table. Choose a value of resistor that is
the closest value higher than the calculated R OVP . In this design
example, a value of 750 k Ω is selected.
Below is the actual value of the minimum OVP trip level with the
selected resistor, applying equation 8:
V OVP(master) = R OVP × I OVPH + 1.25 V
= 750 k Ω × 49 μ A + 1.25 V
= 38.75 V
STEP 4: Determine the inductor. The inductor must be chosen
such that it can handle the necessary input current. In most appli-
cations, due to stringent EMI requirements, the inductor must
operate in continuous conduction mode throughout the whole
input voltage range.
STEP4a: Determine the maximum duty cycle of the system:
Step 2: Determine the LED current by setting resistor R ISET . To
do so, apply equation 2:
D (max) = 1–
V IN (min) × η
V OUT(OVP) + V f(boost)
(12)
= 1–
R ISET = (1.000 / I LED ) × 2320
= (1.000 V / 0.240 A ) × 2320
= 9.67 k Ω
Choose an 9.53 k Ω resistor.
STEP 3: Determine the OVP resistor. The OVP resistor is
connected between the OVP pin and the output voltage of the
converter. The first step is to determine the maximum voltage
based on the LED requirements. Then the regulation voltage of
650 mV should be added, along with 2 V for noise and regulation.
10 V × 0.9
34.65 V+ 0.4 V
= 74.5%
A good approximation of efficiency ( η ) is 90%. The voltage drop
of the boost diode can be approximated to be about 0.4 V.
STEP 4b: Determine the maximum and minimum input current
to the system. The minimum input current dictates the inductor
value. The maximum current rating dictates the current rating of
the inductor.
V OUT(OVP)(min) – V OVP(th) (min)
R OVP =
=
I IN (max) =
=
Given the regulation voltage (V LED ) of theA8509 is 650 mV, the
minimum required voltage can be determined as follows:
V OUT(OVP) = #SERIESLEDS × V f(240) + V LED + 2 V (10)
= 10 × 3.2 V + 0.650 V + 2 V
V OUT(OVP)(min) = 34.65 V
The OVP resistor (ROVP) value can be calculated as:
(11)
I OVPH (min)
34.65 V – 1.11 V
45 μ A
= 745 k Ω
where both I OVP(th) (min) and V OVP(th) (min) are found in the
To calculate the maximum input current, first determine the
required output current:
I OUT = #CHANNELS × I LED
= 4 × 240 mA
= 0.960 A
Then substitute into the formula for maximum input current:
V OUT × I OUT
V IN (min) × η
34.65 V × 0.960 A
10 V × 0.90
= 3.7 A
Allegro MicroSystems, LLC
115 Northeast Cutoff
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com
(13)
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21
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