参数资料
型号: A8509GLPTR-T
厂商: Allegro Microsystems Inc
文件页数: 22/28页
文件大小: 0K
描述: IC LED DVR WHITE 4X120MA 24TSSOP
标准包装: 8,000
拓扑: PWM,SEPIC,升压(升压)
输出数: 4
内部驱动器:
类型 - 主要: 背光
类型 - 次要: 白色 LED
频率: 300kHz ~ 800kHz
电源电压: 9 V ~ 40 V
安装类型: 表面贴装
封装/外壳: 24-TSSOP(0.173",4.40mm)裸露焊盘
供应商设备封装: 24-TSSOP 裸露焊盘
包装: 带卷 (TR)
工作温度: -40°C ~ 105°C
A8509
Wide Input Voltage Range, High Efficiency
4-Channel Fault Tolerant LED Driver
I IN (min) =
=
I L (min)
=
The minimum input current can be calculated as:
V OUT × I OUT
V IN (max) × η
34.65 V × 0.960 A
16 V × 0.90
= 2.31 A
(15)
V SENSE P
R SENSE =
0.086 V
4.28 A
= 0.02 Ω
(19)
STEP 4c: Determining the inductor value. To assure that the
inductor operates in continuous conduction mode, the value of
inductor must be set such that 1 / 2 of the inductor ripple current is
not greater than the average minimum input current.
0.018 Ω is a good value to use for the resistor.
STEP 4f: This step is used to verify that there is sufficient slope
compensation for the inductor chosen. The internal slope com-
pensation value is determined by the following formula:
As a first pass, take I ripple to be 30% of the maximum inductor
current:
? I L = I IN (max) × ( I ripple / I IN (max)) (16)
= 3.72 A × 0.30
Slope Compensation = 2.81×10 –7 × f SW
where f SW is in Hz. Substituting:
= 0.168 V / μ s
With R SENSE = 0.02 Ω this translates to:
(20)
I IN (min) > 1 × ? I L
V IN (min)
L used × f SW
= 1.1 A
Check to make sure that 1 / 2 of the inductor ripple current is less
than I IN (min):
2
2.31 A > 0.56 A
0.168 / 0.02 = 8.4 A/ μ s
Next invert equation 17 and insert the inductor value used in the
design:
? I Lused = × D (max)
(21)
where f SW is in MHz. Substituting:
V IN (min) (17)
× 0.745
=
× 0.745
=
? I Lused × 1 × 10 –6
Inductor Current Slope =
× (1 – D (max))
=
× (1 – 0.745)
The inductor value can be calculated as:
L = × D (max)
? I L × f SW
10 V
1.1 A × 600 kHz
= 10.62 μ H
A good inductor value to use would be L used = 10 μ H.
STEP 4d: Determining the inductor current rating. The inductor
10 V
10 μ H × 600 kHz
= 1.24 A
1
f SW
1.24 A × 1 × 10 –6
1
600 kHz
(22)
(18)
× ? I Lused
I L (min) = I IN (max) +
current rating must be greater than the I IN (max) value plus the
ripple current Δ I L , calculated as:
1
2
= 3.72 A + 0.56 A
= 4.28 A
STEP 4e: Choosing the RSENSE resistor. The sense resistor
value can be calculated as follows:
= 2.91 A / μ s
Note: that the 1×10 –6 is a constant multiplier. This slope should
be smaller than the internal slope compensation.
STEP 5: To determine the resistor values for a switching fre-
quency use figure 9.
STEP 6: Choosing the proper switching diode. The switching
diode must be chosen for three characteristics when it is used in
LED lighting circuitry: reverse voltage rating, current rating, and
reverse current characteristic of the diode.
Allegro MicroSystems, LLC
115 Northeast Cutoff
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com
22
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