参数资料
型号: AD5420AREZ-REEL7
厂商: Analog Devices Inc
文件页数: 19/32页
文件大小: 0K
描述: IC DAC 16BIT 1CH SER 24TSSOP
产品培训模块: Data Converter Fundamentals
DAC Architectures
设计资源: Simplified 16-Bit, 4 mA-to-20 mA Output Solution Using AD5420 (CN0098)
标准包装: 1,000
设置时间: 10µs
位数: 16
数据接口: DSP,MICROWIRE?,QSPI?,串行,SPI?
转换器数目: 1
电压电源: 模拟和数字
功率耗散(最大): 950mW
工作温度: -40°C ~ 85°C
安装类型: 表面贴装
封装/外壳: 24-TSSOP(0.173",4.40mm)裸露焊盘
供应商设备封装: 24-TSSOP 裸露焊盘
包装: 带卷 (TR)
输出数目和类型: 1 电流,单极
采样率(每秒): *
AD5410/AD5420
Data Sheet
Rev. F | Page 26 of 32
R3 and IBIAS both have a tolerance of ±10% and a temperature
coefficient of 30 ppm/°C. Connecting to R3SENSE rather than
AVDD avoids incorporating into R3 internal metal connections
that have large temperature coefficients and result in large
errors. See Figure 49 for a plot of R3 vs. ambient temperature
and Figure 50 for a plot of R3 vs. output current.
40.98
40.96
40.94
40.92
40.90
40.88
40.86
40.84
40.82
40.80
40.78
–40
–20
0
20
40
60
80
100
AMBIENT TEMPERATURE (°C)
R3
RE
SI
ST
ANCE
(
)
07027-
051
IOUT = 12mA
R3 = VR3/(12mA + 444A)
Figure 49. R3 Resistor Value vs. Temperature
42.0
41.8
41.6
41.4
41.2
41.0
40.8
40.6
40.4
40.2
40.0
0
5
10
15
20
25
IOUT (mA)
R3
(
)
07027-
052
TA = 25°C
R3 = VR3/(IOUT + 444A)
Figure 50. R3 Resistor Value vs. IOUT
To eliminate errors due to the tolerances of R3 and IBIAS, a two-
measurement calibration can be performed as the following
example illustrates:
1. Program code 0x1000 and measure IOUT and VR3. In this
example, the measured values are
IOUT = 1.47965 mA
VR3 = 79.55446 mV
2. Program Code 0xF000 and measure IOUT and VR3 again.
The measured values this time are
IOUT = 22.46754 mA
VR3 = 946.39628 mV
Using this information and Equation 2, two simultaneous
equations can be generated from which the values of R3 and
IBIAS can be calculated as follows:
OUT
R
BIAS
R
OUT
I
R
V
I
R
V
I
=
=
3
Simultaneous Equation 1
00147965
.
0
3
07955446
.
0
=
R
I
BIAS
Simultaneous Equation 2
02246754
.
0
3
94639628
.
0
=
R
I
BIAS
From these two equations,
302
.
41
3
=
R
Ω and
5
.
446
=
BIAS
I
μA
And Equation 2 becomes
A
V
I
R
OUT
5
.
446
302
.
41
3
=
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