参数资料
型号: IR3500AMPBF
厂商: International Rectifier
文件页数: 41/48页
文件大小: 0K
描述: IC CTRL XPHASE3 VR11.0 32-MLPQ
标准包装: 100
系列: XPhase3™
应用: 处理器
电流 - 电源: 6.5mA
电源电压: 4.75 V ~ 7.5 V
工作温度: 0°C ~ 100°C
安装类型: 表面贴装
封装/外壳: 32-VFQFN 裸露焊盘
供应商设备封装: 32-MLPQ(5x5)
包装: 管件
IR3500A
Calculate constant K P, the ratio of inductor peak current over average current in each phase,
K P =
? m m + 1 ?
? ?
? V I ? D ? ( 1 ? D ) ? n ? ( D ? n ) ? ( n ? D ) ?
( I LIMIT / n ) ? L ? f sw ? 2 ? D ? ( 1 ? D )
=
? 0 0 + 1 ?
? ?
? 12 ? 0 . 108 ? ( 1 ? 0 . 108 ) ? 6 ? ( 0 . 108 ? 6 ) ? ( 6 ? 0 . 108 ) ?
( 135 / 6 ) ? 0 . 1 u ? 800 k ? 2 ? 0 . 108 ? ( 1 ? 0 . 108 )
= 0 . 126
R OCSET = [
I LIMIT
n
? R L _ MAX ? ( 1 + K P ) + V CS _ TOFST ] ? G CS / I OCSET
= (
135
6
? 0 . 64 * 10 ? 3 ? 1 . 126 + 0 . 3 * 10 ? 3 ) ? 34 /( 40 * 10 ? 6 ) = 14 k ?
Calculate constant K P, the ratio of inductor peak current over average current in each phase,
No Load Output Voltage Setting Resistor R VSETPT and Adaptive Voltage Positioning Resistor R DRP
From Figure 24, the bias current of VSETPT pin is 40uA with R OSC =15k .
R VSETPT =
V O _ NLOFST
I VSETPT
=
20 * 10 ? 3
40 * 10 ? 6
= 500 ?
VCCL Programming Resistor R VCCLFB1 and R VCCLFB2
Choose VCCL=7V to maximize the converter efficiency. Pre-select R VCCLFB1 =20k , and calculate R VCCLFB2.
R VCCLFB 2 =
R VCCLFB 1 * 1. 19
VCCL ? 1 . 19
=
20 * 10 3 * 1. 19
7 ? 1 . 19
= 4 . 05 k ?
VCCL Drive Resistor R VCCLDRV
The maximum drive current for the linear regulator is dependent on the type of MosFET used. For this
example, it’s assumed that IR6622/ IRF6691 are used as buck switches.
I drive _ avg = [ ( 47 n + 11 n ) ? 800 k + 10 mA ] ? 6 = 350 mA
(19)
The minimum input voltage is assumed to be 10.5 V and VCCL is fixed at 6.5V for this design.
R VCCLDRV =
10. 5 V ? 0 .7 V ? 6.5 V
350 mA / 70
= 660 ?
(20)
Choose a transistor with β (min) of 70. The maximum input voltage is assumed 13.5 V,
13 . 5 V ? 0 . 7 ? 6 . 5
660 ?
= 9 . 5 mA < 10 mA
(21)
Thermistor R THERM and Over Temperature Setting Resistors R HOTSET1 and R HOTSET2
Choose NTC thermistor R THERM =2.2k , which has a constant of B THERM =3520, and the NTC thermistor
resistance at the allowed maximum temperature T MAX is,
R TMAX = R THERM * EXP [ B THERM * (
1
T L _ MAX
?
1
T _ ROOM
)] = 2 . 2 * 10 3 * EXP [ 3520 * (
1
273 + 115
?
1
273 + 25
)] = 142 ?
Select R HOTSET2 = 931
to linearize the NTC, which has non-linear characteristics in the operational temperature
range. Then calculate R HOTSET1 corresponding to the allowed maximum temperature TMAX.
Page 41 of 48
July 28, 2009
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