参数资料
| 型号： | LT3510IFE#TRPBF |
| 厂商： | Linear Technology |
| 文件页数： | 17/30页 |
| 文件大小： | 0K |
| 描述： | IC REG BUCK ADJ 2A DL 20TSSOP |
| 标准包装： | 2,500 |
| 类型： | 降压（降压） |
| 输出类型： | 可调式 |
| 输出数： | 2 |
| 输出电压： | 0.8 V ~ 23.8 V |
| 输入电压： | 3.1 V ~ 25 V |
| PWM 型： | 电流模式 |
| 频率 - 开关： | 250kHz ~ 1.5MHz |
| 电流 - 输出： | 2A |
| 同步整流器： | 无 |
| 工作温度： | -40°C ~ 125°C |
| 安装类型： | 表面贴装 |
| 封装/外壳： | 20-TSSOP（0.173"，4.40mm 宽）裸露焊盘 |
| 包装： | 带卷 (TR) |
| 供应商设备封装： | 20-TSSOP-EP |
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LT3510
APPLICATIONS INFORMATION
Table 2
where I OUT(MAX) is the maximum load current, and
VENDOR
Taiyo Yuden
AVX
Kemet
Sanyo
Panasonic
TDK
TYPE
Ceramic X5R, X7R
Ceramic X5R, X7R
Tantalum
Tantalum
TA Organic
AL Organic
TA/AL Organic
AL Organic
Ceramic X5R, X7R
SERIES
T491, T494, T495
T520
A700
POSCAP
SP CAP
V BST(MIN) is the minimum boost voltage to fully saturate
the switch.
Figure 5 shows four ways to arrange the boost circuit. The
BST pin must be more than 1.4V above the SW pin for
full ef?ciency. Generally, for outputs of 3.3V and higher
the standard circuit (Figure 5a) is the best. For outputs
between 2.8V and 3.3V, replace the D2 with a small Schottky
diode such as the PMEG4005. For lower output voltages
the boost diode can be tied to the input (Figure 5b). The
circuit in Figure 5a is more ef?cient because the BST
Catch Diode
The diode D1 conducts current only during switch off
time. Use a Schottky diode to limit forward voltage drop to
increase ef?ciency. The Schottky diode must have a peak
reverse voltage that is equal to regulator input voltage and
sized for average forward current in normal operation.
Average forward current can be calculated from:
pin current comes from a lower voltage source. Figure
5c shows the boost voltage source from available DC
sources that are greater than 3V. The highest ef?ciency is
attained by choosing the lowest boost voltage above 3V.
For example, if you are generating 3.3V and 1.8V and the
3.3V is on whenever the 1.8V is on, the 1.8V boost diode
can be connected to the 3.3V output. In any case, you
must also be sure that the maximum voltage at the BST
I D(AVG) =
I OUT
V IN
? ( V IN – V OUT )
pin is less than the maximum speci?ed in the Absolute
Maximum Ratings section.
The only reason to consider a larger diode is the worst-
case condition of a high input voltage and shorted output.
With a shorted condition, diode current will increase to a
typical value of 3A, determined by the peak switch current
limit of the LT3510. This is safe for short periods of time,
but it would be prudent to check with the diode manu-
facturer if continuous operation under these conditions
can be tolerated.
BST Pin Considerations
The capacitor and diode tied to the BST pin generate
a voltage that is higher than the input voltage. In most
cases a 0.47μF capacitor and fast switching diode (such
as the CMDSH-3 or FMMD914) will work well. Almost
any type of ?lm or ceramic capacitor is suitable, but the
ESR should be <1 Ω to ensure it can be fully recharged
during the off time of the switch. The capacitor value can
be approximated by:
The boost circuit can also run directly from a DC voltage
that is higher than the input voltage by more than 3V, as
in Figure 5d. The diode is used to prevent damage to the
LT3510 in case V X is held low while V IN is present. The
circuit saves several components (both BST pins can be
tied to D2). However, ef?ciency may be lower and dissipa-
tion in the LT3510 may be higher. Also, if V X is absent, the
LT3510 will still attempt to regulate the output, but will do
so with very low ef?ciency and high dissipation because
the switch will not be able to saturate, dropping 1.5V to
2V in conduction.
The minimum input voltage of an LT3510 application is
limited by the minimum operating voltage (<3V) and by
the maximum duty cycle as outlined above. For proper
start-up, the minimum input voltage is also limited by
the boost circuit. If the input voltage is ramped slowly, or
the LT3510 is turned on with its SS pin when the output
is already in regulation, then the boost capacitor may not
be fully charged. Because the boost capacitor is charged
C BST =
B ? ( V OUT – V BST(MIN) ) ? f
I OUT(MAX) ? DC
with the energy stored in the inductor, the circuit will rely
on some minimum load current to get the boost circuit
running properly. This minimum load will depend on
3510fe
17
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